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creativ13 [48]
3 years ago
11

Which set of numbers below DO NOT make a triangle? 0 7,7,7 O 6,3,3 0 3,4,5 O 5, 11,7

Mathematics
1 answer:
Hoochie [10]3 years ago
5 0

Answer:

3,4,5

Step-by-step explanation:

All you have to do is use the Triangle Inequality Theorem, which states that the sum of two side lengths of a triangle is always greater than the third side. If this is true for all three combinations of added side lengths, then you will have a triangle therefore 3,4,5 is not triangle.

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Making art and can help you find a difference 13 - 5 ​
Genrish500 [490]

Answer:

Here's how to solve

Step-by-step explanation:

Okay so 13 -5

What can you add to 5 to get 13?

5+5=10

5+6=11

5+7=12

5+8=13

8 would be your answer.

5 0
3 years ago
Gannon has deposited $742 in a savings account that earns interest at a rate of 3.4% compounded monthly. What will the account b
marta [7]
Firstly, solve the effective annual interest (ieff) with the equation,
 
                          ieff = (1 + i/m)^m -1

where i is the interest rate and m is the number of times the interest is compounded in a year. In this problem, m is 12

Substituting the values, 
                            ieff = (1 + 0.034/12)^12 - 1 =0.03453

To solve for the future (F) amount of the present investment (P), 
                                       
                                        F = P x (1 + ieff)^n

where n is number of years.
 
                                        F = ($742) x (1 + 0.03453)^15

Thus, the answer is $1234.76. 


 
                

7 0
3 years ago
Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
Ivenika [448]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

P(x = 7) = 11C7 × 0.6^(11-7) × 0.4^7 = 0.15

P(x lesser than or equal to 7) = 0.004 + 0.027 + 0.089 + 0.177 + 0.24 + 0.22 + 0.15 + 0.07 = 0.977

c) P(x greater than or equal to 5) = 1 - P(x lesser than or equal to 4) = 1 - (0.004 + 0.027 + 0.089 + 0.177 + 0.24) = 1 - 0.537 = 0.463

d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

5 0
3 years ago
g Refer to these data for the next set of questions: The JMP output is below. Use it to answer the following questions. Write th
mariarad [96]
Hope you find this answer I need points
5 0
3 years ago
Anyone know the answer to this question???
Katyanochek1 [597]

They want you to write the number in index form.

The number is 5N^2, where N = 3 x 5^2 x x^3

So:

5N^2 = 5 x (3 x 5^2 x x^3)^2

         = 5 x (3^2 x 5^4 x x^6)

         = 3^2 x 5^5 x x^6

or a bit neater looking:  3² ₓ 5⁵ ₓ x⁶

5 0
3 years ago
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