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AlekseyPX
2 years ago
10

A cleaning solution is made from vinegar, lemon juice, and water. The table below shows the part of the total solution that is i

n each element. Mr. Allen needs 100 mL of a solution that is 30% vinegar, 15% lemon juice, and 55% water. How much of solution A will Mr. Allen need to make his cleaning solution?
a. 0 mL
b. 10 mL
c. 30 mL
d. 50 mL

Mathematics
2 answers:
Natali [406]2 years ago
6 0

Answer:

30 ml (c)

Step-by-step explanation:

dexar [7]2 years ago
6 0

Answer:

30 mL :)

Step-by-step explanation:

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You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu
aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to 180^{o}.

Let the exterior angle be represented by x^{o}, and the three interior angles of the triangle be represented by a^{o}, b^{o} and c^{o}.

Assume that the vertex angle c^{o} is the linear pair to the exterior angle x^{o}.

i.e            x^{o} + c^{o} = 180^{o}  (sum of angles on a straight line)

Thus,

i. a^{o} +  b^{o} = x^{o}  (sum of two opposite interior angles is equal to an exterior angle)

⇒ a^{o}  = x^{o} - b^{o}

Also,

b^{o}  = x^{o} - a^{o}

But,

a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

⇒ c^{o} = 180^{o} - (a^{o} +  b^{o})

and

a^{o} + b^{o} = 180^{o} - c^{o}

ii. a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

a^{o} = 180^{o} - (b^{o} + c^{o})

Also,

a^{o} +  b^{o} = x^{o}

⇒ b^{o} = x^{o} - a^{o}

c^{o} = 180^{o} - x^{o}

8 0
2 years ago
enton is shopping for clothes during a special event. He pays $24.99 for a pair of jeans and $5.25 for a clearance-priced shirt.
Marianna [84]

Answer$18.12

Step-by-step explanation:

24.99+5.25-12.12=$18.12

7 0
2 years ago
What's the flux of the vector field F(x,y,z) = (e^-y) i - (y) j + (x sinz) k across σ with outward orientation where σ is the po
emmasim [6.3K]
\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS
\displaystyle\iint_\sigma\mathbf F\cdot\mathbf n\,\mathrm dS
\displaystyle\iint_\sigma\mathbf F\cdot\left(\frac{\mathbf r_u\times\mathbf r_v}{\|\mathbf r_u\times\mathbf r_v\|}\right)\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dA
\displaystyle\iint_\sigma\mathbf F\cdot(\mathbf r_u\times\mathbf r_v)\,\mathrm dA

Since you want to find flux in the outward direction, you need to make sure that the normal vector points that way. You have

\mathbf r_u=\dfrac\partial{\partial u}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=\mathbf k
\mathbf r_v=\dfrac\partial{\partial v}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=-2\sin v\,\mathbf i+\cos v\,\mathbf j

The cross product is

\mathbf r_u\times\mathbf r_v=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&1\\-2\sin v&\cos v&0\end{vmatrix}=-\cos v\,\mathbf i-2\sin v\,\mathbf j

So, the flux is given by

\displaystyle\iint_\sigma(e^{-\sin v}\,\mathbf i-\sin v\,\mathbf j+2\cos v\sin u\,\mathbf k)\cdot(\cos v\,\mathbf i+2\sin v\,\mathbf j)\,\mathrm dA
\displaystyle\int_0^5\int_0^{2\pi}(-e^{-\sin v}\cos v+2\sin^2v)\,\mathrm dv\,\mathrm du
\displaystyle-5\int_0^{2\pi}e^{-\sin v}\cos v\,\mathrm dv+10\int_0^{2\pi}\sin^2v\,\mathrm dv
\displaystyle5\int_0^0e^t\,\mathrm dt+5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv

where t=-\sin v in the first integral, and the half-angle identity is used in the second. The first integral vanishes, leaving you with

\displaystyle5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv=5\left(v-\dfrac12\sin2v\right)\bigg|_{v=0}^{v=2\pi}=10\pi
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3 years ago
Which of the following is the graph of y=-(x-2) – 5?
svlad2 [7]

Answer:

465

Step-by-step explanation:

7 0
2 years ago
Is 3/10 and 0.3 equivalent
dolphi86 [110]
Yes, they are! To divide something by ten, just move the decimal left one spot.
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