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VARVARA [1.3K]
3 years ago
8

Please help with this one question

Mathematics
2 answers:
Gennadij [26K]3 years ago
5 0
Hi.
your answer is 89.625 .
hope this helps!!!
Nikitich [7]3 years ago
3 0
The average is 89.625
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Use undetermined coefficients to find the particular solution to 7t + 5=y''+y'-4y У, (t) - Preview Get help: Video Points possib
lions [1.4K]

Suppose y_p=a_0+a_1t is a solution to the ODE. Then {y_p}'=a_1 and {y_p}''=0, and substituting these into the ODE gives

a_1-4(a_0+a_1t)=7t+5\implies\begin{cases}-4a_1=7\\-4a_0+a_1=5\end{cases}\implies a_0=-\dfrac{27}{16},a_1=-\dfrac74

Then the particular solution to the ODE is

y_p=-\dfrac{27}{16}-\dfrac74t

5 0
3 years ago
25 POINTS WILL MARK RIGHT ANSWER AS BRAINLIEST! What is the value of x to the nearest tenth?
andreyandreev [35.5K]

Answer:

The value of x is 2.5 to the nearest tenth

Step-by-step explanation:

* Lets revise the trigonometry functions

- In any right angle triangle:

# The side opposite to the right angle is called the hypotenuse

# The other two sides are called the legs of the right angle

* If the name of the triangle is ABC, where B is the right angle

∴ The hypotenuse is AC

∴ AB and BC are the legs of the right angle

- ∠A and ∠C are two acute angles

- For angle A

# sin(A) = opposite/hypotenuse

∵ The opposite to ∠A is BC

∵ The hypotenuse is AC

∴ sin(A) = BC/AC

# cos(A) = adjacent/hypotenuse

∵ The adjacent to ∠A is AB

∵ The hypotenuse is AC

∴ cos(A) = AB/AC  

# tan(A) = opposite/adjacent

∵ The opposite to ∠A is BC

∵ The adjacent to ∠A is AB

∴ tan(A) = BC/AB

* Now lets solve the problem

∵ x is opposite to the angle of measure 23°

∵ 6 is adjacent to the angle of measure 23°

∴ tan(23°) = x/6 ⇒ × 6 to both sides

∴ x = 6 × tan(23°) = 2.5

* The value of x is 2.5 to the nearest tenth

7 0
3 years ago
Read 2 more answers
A power line stretches from the top of a building to the ground. The power line is 100ft. long and the building is 50 ft. tall.
Nutka1998 [239]

Answer:

86.6 ft.

Step-by-step explanation:

6 0
3 years ago
6m^2 + 7n<br>Identify the constant, variable, and terms​
Leokris [45]
<h3>Answer:</h3>

<u>Given equation</u> :- 6m² + 7n

where,

  • <u>Constant</u> = 0.
  • <u>Variable</u> = m, n.
  • <u>Terms</u> = 6m² , 7n.
6 0
3 years ago
The temperature of a weather station was 12.8 °F at midnight and fell 1.4 °F each hour for six hours. Which of the following sol
Len [333]

Answer:

Let's try to find a linear relation like:

T(h) = a*h + b

where a is the slope and b is the y-intercept.

h is the number of hours after midnight.

T is the temperature at the time defined by h.

We know that at midnight, the temperature is 12.8°F.

At midnight, we have h = 0, then:

T(0) = a*0 + b = 12.8°F

       b = 12.8°F

Now we know that our function is:

T(h) = a*h + 12.8°F

We also know that the temperature fell 1.4 °F each hour for six hours.

Then the slope will be -1.4°F

We can write the linear relationship as:

T(h) = -1.4°F*h + 12.8°F     (for 0 ≤ h ≤ 6)

Where we have a restriction in the possible values of h, because we know that this model only works for six hours after midnight,

3 0
3 years ago
Read 2 more answers
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