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Fofino [41]
3 years ago
9

Consider the function f(x)=6x+5 (A) find it’s average rate of change by changing x=1 to x=5

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
8 0

Answer: I really don’t know

Step-by-step explanation: I need help with this as well. I’m really sorry if you were looking for a real answer

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F(x) = 3x + 12, g(x) = 3x - 1;<br> =<br> =<br> Find (fºg)(x).
MissTica

\text{Given that,}\\\\f(x) = 3x +12, ~ ~ g(x) = 3x -1\\\\(f \circ g)(x)\\\\=f(g(x))\\\\=f(3x-1)\\\\=3(3x-1) +12\\\\=9x - 3 +12\\\\=9x +9\\\\=9(x+1)

3 0
2 years ago
1. What is the slope between the points (2,-5) and (8,3)? *<br><br> Show work please
hjlf

Answer:

\sf m = \dfrac{4}{3}

Step-by-step explanation:

Given, \sf (x_1, ~ y_1) = (2, -5) and \sf (x_2, ~ y_2) = (8, 3)

The slope formula is, \sf m = \dfrac{y_2 - y_1}{x_2 - x_1}

\sf m = \dfrac{3 - (-5)}{8 - 2}

\sf m = \dfrac{8}{6}

\bf m = \dfrac{4}{3}

6 0
2 years ago
Can I get help with finding the Fourier cosine series of F(x) = x - x^2
trapecia [35]
Assuming you want the cosine series expansion over an arbitrary symmetric interval [-L,L], L\neq0, the cosine series is given by

f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx

You have

a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx
a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}
a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)
a_0=-\dfrac{2L^2}3

a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}

and so

a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}

So the cosine series for f(x) periodic over an interval [-L,L] is

f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx
4 0
3 years ago
Which unit is not a customary unit? <br> A. gallon<br> B. ounce<br> C. gram<br> D. cup
SOVA2 [1]

Answer:

D.Cup

Step-by-step explanation:

We humans do not use the term Cup anymore. We now use things like Grams,Ounces,Gallons,Or Quarts.

3 0
3 years ago
Square GYTD has vertices G(−4,3) , Y(0, 3) , T(0,−1) and D(−4,−1) . ​ Square GYTD ​ is translated 2 units left and 2 units up to
Sliva [168]

we know that

If square GYTD ​ is translated 2 units left and  2 units up to produce square G'Y'T'D'

that means

the rule of transformation is

(x,y)-------> (x-2,y+2)

<u>Find the coordinates of the image</u>

G (-4,3)------->G'(-4-2,3+2)=G'(-6,5)

Y (0,3)------->Y'(0-2,3+2)=Y'(-2,5)

T (0,-1)------->T'(0-2,-1+2)=T'(-2,1)

D (-4,-1)------->D'(-4-2,-1+2)=D'(-6,1)

therefore

<u>the answer is the option</u>

G'(−6, 5), Y'(−2, 5), T'(−2, 1) , and D′(−6, 1)

6 0
3 years ago
Read 2 more answers
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