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Sidana [21]
3 years ago
12

Given cos A = .34 find angle A in degrees. Round your answer to the nearest hundredth

Mathematics
1 answer:
Eva8 [605]3 years ago
7 0
Given:

The equation cos A = 0.34

Required:

The value of A in degrees rounded to the nearest hundredths.

Solution:

Solve for the value of A, we use the trigonometric function of arc cosine.

A = arc cos(0.34)

A = 70.12°
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I will assume that this question is about scientific notation (also assuming that the first number is 3.4*10^2), where you can arrange the numbers by the exponent of the 10, so from least to greatest:
8.11*10^{-3}, 3.4*10^{2}, 435, and 1.2*10^{7}
6 0
3 years ago
Socket set for $36.00 with 40% off plus 8.25 % sales tax. How much do I owe?
OlgaM077 [116]

whatever% of anything is just (whatever/100) * anything.


so the socket set has a 40% off, what is 40% of 36?  well, is just (40/100) * 36, or 14.4, that's the discount, so the sale price is 36 - 14.4, or 21.6.


plus the 8.25% taxation, what is 8.25% of 21.6?  well, is just (8.25/100) * 21.6, or 1.782.

so the total price is 21.6 + 1.782, or 23.382, or about 23 bucks and 38 cents.

3 0
3 years ago
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The base parking charge at a mall on a Sunday is $2 per hour. If a vehicle is parked for 4 hours, only $6 is charged. What perce
chubhunter [2.5K]
2 dollars = 1 hour
8 dollars = 4 hours
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A circle has a diameter of 6 centimeters what is the approximate area of the circle​
KiRa [710]

Answer:

28.26 cm^{2}

Step-by-step explanation:

The radius is half of the diameter. 6/2 = 3, so the radius of this circle is 3 cm.

The formula for the area of a circle is: πr^{2}

Plugging 3 into the radius, we have:

3^{2} × π =

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We can round π to 3.14

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7 0
2 years ago
If sin ⁡x=725, and 0 ∠ x ∠ pi/2, what is the tan (x - pi/4)
krok68 [10]

Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

<u>Step-by-step explanation:</u>

Here we have ,  sin ⁡x=7/25( given sin x = 725 which is not possible ) , 0 . Let's find tan (x - pi/4):

⇒ Tanx = \frac{sinx}{cosx}

⇒ Tanx = \frac{sinx}{\sqrt{1-(sinx)^{2}}}

⇒ Tanx = \frac{\frac{7}{25}}{\sqrt{1-(\frac{7}{25})^{2}}}

⇒ Tanx = {\frac{7}{25}}{\sqrt{(\frac{625}{625-49})^{}}}

⇒ Tanx = {\frac{7}{25}}(\frac{25}{24} )

⇒ Tanx = {\frac{7}{24}}

Now , Tan(x-\frac{\pi }{4}) = \frac{Tanx - Tan(\frac{\pi }{4} )}{1+ Tanx(Tan(\frac{\pi }{4} )}

⇒ Tan(x-\frac{\pi }{4}) = \frac{Tanx -1}{1+ Tanx(1)}

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7}{24}  -1}{1+\frac{7}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7-24}{24} }{\frac{7+24}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{24} (\frac{24}{31} )

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

7 0
3 years ago
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