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3 years ago

I give you brainless if you get it right

Mathematics

2 answers:

Mariana [72]3 years ago

7 0

Answer:

The answer is

D. (2,-2)

Delvig [45]3 years ago

3 0

Answer:

(2, -2) completes square ABCD.

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How to do this question plz answer me step by step plzz plz plz plz

Step2247 [10]

Answer: 25.6

First, notice that there is 1 adult and 2 children.

A normal adult ticket costs 24. But it's 1/3 off, so 24 * 1/3 = 8 off. That means with the Railcard, it only costs 24 - 8 = 16.

Next, one child ticket costs 12. But it's 60% = 3/5 off, so 12 * 3/5 = 7.2 off. That means with the Railcard, it only costs 12 - 7.2 = 4.8.

Remember there are 2 children, so we multiply by 2 to get 4.8 * 2 = 9.6 for the children.

Final answer: 1 adult + 2 children = 16 + 9.6 = 25.6.

Hope that helped,

-sirswagger21

8 0

3 years ago

Read 2 more answers

What is the value of begin expression . . . 5 raised to the third power, minus 4, times 3 raised to the second power, plus 13 .

AveGali [126]

5^3-4*3^2+13=102
So the correct answer is C.
i miss having fun math homework

6 0

3 years ago

Can someone help me on this point slope thing i don’t know what i’m doing

bezimeni [28]

The equation would be y - 2 = -3(x + 9)

6 0

4 years ago

4. Automobile policies are separated into two groups: low-risk and high-risk. Actuary Rahul examines low-risk policies, continui

ANTONII [103]

Answer:

Step-by-step explanation:

for n ∈ N

Since Actuary Rahul examines low-risk policies, continuing until a policy with a claim is found and then stopping.

∴ the probability that Actuary Rahul examines exactly n policies

$(0.9)^{n-1}.(0.1)---(1)$

the probability that Actuary Toby examines more than exactly n policies

$(0.8)^n---(2)$

Given that policies are actually independent

∴ the probability that the event (1) and (2) happens simultaneously is

$(0.9)^{n-1}*(0.1)*(0.8)^n$

∴ the probability that Actuary Rahul examines fewer policies than Actuary Toby

$\sum ^\infty _{n=1} (0.9)^{n-1}*(0.1)*(0.8)^n\\\\=(\frac{0.1}{0.9} \sum ^\infty _{n=1}(0.72)^n\\\\=\frac{1}{9} (\frac{0.72}{0.28} )\\\\=\frac{2}{7} \\\\=0.2857$

<h3>the probability that Actuary Rahul examines fewer policies than Actuary Toby is 0.2857</h3>

5 0

3 years ago

For what values of b are the vectors \langle -46, b, 10 \rangle and \langle b, b^2, b \rangle orthogonal

Jet001 [13]

Answer:

b = 6 or b = -6 (non-zero vectors)

b = 0 (zero vector)

Step-by-step explanation:

Two vectors $\vec{a}=\langle a_1,a_2,a_3\rangle$ and $\vec{b}=\langle b_1,b_2,b_3\rangle$ are orthogonal if their dot product is equal to 0, or in other words