PLEASE HELPPPP

Mathematics

1 answer:

valkas [14]3 years ago

3 0

Answer:

$y = -\frac{5}{2}x + 6$

Step-by-step explanation:

Using a point (4, -4) and the slope of the line that passes through it, m = -⁵/2, we can generate an equation by using the point-slope form equation of a line given as y - b = m(x - a).

Where,

(a, b) = (4, -4)

m = -⁵/2

Plug in the values

y - (-4) = -⁵/2(x - 4)

y + 4 = (-5x + 20)/2

Multiply both sides by 2

2y + 8 = -5x + 20

Subtract both sides by 8

2y = -5x + 20 - 8

2y = -5x + 12

Divide both sides by 2

y = -⁵/2x + 12/2

$y = -\frac{5}{2}x + 6$ (equation in slope-intercept form)

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Hello,..... I will mark you as a brainliest

madam [21]

Answer:

5 jumps

Step-by-step explanation:

Personally I would write it out, although there surely is a formula for it.

3 fall to 2 - 5 fall to 4 - 7 fall to 6 - 10 fall to 9 - 12.

This makes 5 jumps, since once he is out he won't fall back in.

8 0

3 years ago

Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt. xy = 4 (a) Find dy/d

kompoz [17]

Answer:

a) -0.9375

b) 1.25

Step-by-step explanation:

We are given the following in the question:

$f(x,y) = 4$

where x and y are both differentiable functions of t.

a) x = 8 and dx/dt = 15

$\\xy = 4\\\\y = \dfrac{4}{x}\\\\y = \dfrac{4}{8}=\dfrac{1}{2}\\\\\dfrac{d(f(x,y))}{dt} = 0\\\\x\dfrac{dy}{dt} + y\dfrac{dx}{dt} = 0\\\\8\dfrac{dy}{dt} + \dfrac{1}{2}(15) = 0 \\\\\dfrac{dy}{dt} = \dfrac{1}{8}\times \dfrac{-15}{2}\\\\\dfrac{dy}{dt} = -\dfrac{15}{16}\\\\\dfrac{dy}{dt}=-0.9375$

b) x = 1 and dy/dt = –5

$xy = 4\\\\y = \dfrac{4}{x}\\\\ y= 4\\\\\dfrac{d(f(x,y))}{dt} = 0\\\\x\dfrac{dy}{dt} + y\dfrac{dx}{dt} = 0\\\\(1)(-5) + 4\dfrac{dx}{dt} = 0 \\\\\dfrac{dx}{dt} = \dfrac{5}{4}\\\\\dfrac{dx}{dt} = 1.25$