1/sin^2x-1/tan^2x=
1/sin^2x-1/ (sin^2x/cos^2x)<<sin tan= sin/cos>>
= 1/sin^2x- cos^2x / sin^2x
= (1- cos^2x) / sin^2x <<combining into a single fraction>>
sin^2 x / sin^2x <<since 1- cos^2 x sin^2 x
=1
this simplifies to 1.
Answer:
2
Step-by-step explanation:
Its the only graph that matches.
Answer:
2/5
Step-by-step explanation:
Answer:
42.42in³
Step-by-step explanation:
This problem bothers on the mensuration of solid shapes, a cone
Step one
We know that the volume of a cone is
V= 1/3πr²h
Given data
Diameter d= 6 inches
Radius r= diameter/2= 6/2= 3 inches
Height h = 4.5 inches
Step two
Substituting our given data we have
Volume = 1/3*3.142*3²*4.5
V= 1/3*3.142*9*4.5
V= 127.251/3
V= 42.42in³
Answer:
b
Step-by-step explanation:
