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3 years ago

The equation of line AB is (y-3) = 5 (x - 4). What is the slope of a line perpendicular to line AB?

Mathematics

2 answers:

Nastasia [14]3 years ago

5 0

Y - 3 = 5(x - 4)
y - 3 = 5x - 20
y = 5x - 20 + 3 = 5x - 17
=> slope = 5

For perpendicular line, m2 = -1/m1 = -1/5

Greeley [361]3 years ago

5 0

Perpendicular lines are lines that intersect. The angle made by their intersection is a right angle. To know if 2 lines are perpendicular is through their slopes. The slope of the other line must be the negative reciprocal of the slope of the first. Since the slope of line AB is 5 hence the slope of the other line must be -1/5. C is the answer.

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4, 12, and 18 in two different ways

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For which value of theta is sin theta equals -1?

Olin [163]

Answer:

The value of Ф is 3π/2

Step-by-step explanation:

* Lets revise the angle Ф in the four quadrant

∵ r = √(x² + y²) ⇒ square the two sides

∴ x² + y² = r²

∵ r = 1

∴ x² + y² = 1

∵ cos² Ф + sin² Ф = 1

∵ x is the adjacent side to Ф and y is the opposite side to Ф

∴ x = cos Ф and y = sin Ф

- At point (1 , 0)

∵ x = 1 , y = 0

∴ cos Ф = 1 and sin Ф = 0

∵ The positive part of x-axis represents the angle 0 and 2π

∴ cos 0 and 2π are 1 and sin 0 and 2π are 0

- At point (0 , 1)

∵ x = 0 , y = 1

∴ cos Ф = 0 and sin Ф = 1

∵ The positive part of y-axis represent the angle π/2

∴ cos π/2 is 0 and sin π/2 is 1

- At point (-1 , 0)

∵ x = -1 , y = 0

∴ cos Ф = -1 and sin Ф = 0

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∴ cos π is -1 and sin π is 0

- At point (0 , -1)

∵ x = 0 , y = -1

∴ cos Ф = 0 and sin Ф = -1

∵ The negative part of y-axis represent the angle 3π/2

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3 years ago

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Can someone please explain to me how to get this answer?

SIZIF [17.4K]

Answers:
A = 120
b = 45.0
c = 33.2

Side Note: only one triangle is possible
See attached for a visual. I used GeoGebra to draw the triangle.

-------------------------------------------------------------
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Explanation:

We are given the following information
B = 35
C = 25
a = 68

We need to find the following
A, b, c

where the lower case letters represent the side lengths; the upper case letters are the angles. The angles are opposite their corresponding sides. For instance, side lowercase b is opposite angle uppercase B. The other letters are positioned the same way.

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First use the idea that for any triangle, the three angles (A,B,C) must add to 180 degrees
A+B+C = 180
Replace B and C with 35 and 25. Solve for angle A
A+35+25 = 180
A+60 = 180
A+60-60 = 180-60
A = 120

Now that we know the three angles A = 120, B = 35, C = 25, we can find the missing sides 'b' and 'c'

-----------------------

We will use the law of sines to find side b
sin(A)/a = sin(B)/b
sin(120)/68 = sin(35)/b
b*sin(120) = 68*sin(35) <<--- cross multiply
b = 68*sin(35)/sin(120)
b = 45.037013350222 <<--- use a calculator; this value is approximate
b = 45.0 <<--- round to the nearest tenth

-----------------------

Do the same for side c
sin(A)/a = sin(C)/c
sin(120)/68 = sin(25)/c
c*sin(120) = 68*sin(25) <<--- cross multiply
c = 68*sin(25)/sin(120)
c = 33.1838323365404 <<--- use a calculator; this value is approximate
c = 33.2 <<--- round to the nearest tenth