GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped
Answer:
no solution
Step-by-step explanation:
-4(x+5)=-4x-30
-4x-20=-4x+30
no solution
x cancel
The function given can be classified as a function. That is option C.
<h3>What is a function in mathematics?</h3>
Function can be defined as the expression that has both an x domain value and a y range value and it's being classified based on the quality of these values.
A function can be represented based on their roster forms.
Using the function equation given, f(X) = 10.2^2
Here, the first element is the domain or the x value and the second element is the range or the f(x) value of the function.
Learn more about arithmetic function here:
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