Answer:
m ≤ 27 or m > 11
m is all real number since we have the or
Step-by-step explanation:
m − 11 ≤ 16 or 15 − 2m < −7
Lets solve the one on the left first
m − 11 ≤ 16
Add 11 to each side
m-11+11 ≤ 16 +11
m ≤ 27
Now lets solve the one on the right
15 − 2m < −7
Subtract 15 from each side
15 −15- 2m < −7 -15
-2m < -22
Divide by -2, remembering to flip the inequality
-2m/-2 > -22/-2
m > 11
Answer:
Step-by-step explanation:
y = x .....(1)
.... (2)
By solving equation (1) and equation (2)
or 
x = 0, x = 1
y = 0, y = 1
A = 
A = 
A = ![\frac{2}{3}[x^\frac{3}{2}]_{0}^{1}-\frac{1}{2}[x^2]_{0}^{1}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%5Bx%5E%5Cfrac%7B3%7D%7B2%7D%5D_%7B0%7D%5E%7B1%7D-%5Cfrac%7B1%7D%7B2%7D%5Bx%5E2%5D_%7B0%7D%5E%7B1%7D)
A = 
A =
Answer:
a) Эx ∈ R ⊇ x³ = 2
b) ∀x ∈ R, x² ≥ 0
c) Эx ∈ R ⊇ x³ = x
d) ∀x ∈ R, x ≤ x²
Step-by-step explanation:
Given the data in the question;
let us first go through some symbols and their possible meanings;
Э ⇒ there exists
∀ ⇒ for all
∈ ⇒ belongs to or set membership or element of the set
⊇ ⇒ such that
now;
a) There is a number whose cube is equal to 2
let x represent the number; so
Эx ∈ R ⊇ x³ = 2
b) The square of every number is at least 0
x² ≥ 0, ∀x ∈ R
∀x ∈ R, x² ≥ 0
c) There is a number that is equal to its square
Эx ∈ R ⊇ x³ = x
d) Every number is less than or equal to its square.
x ≤ x², ∀x ∈ R
∀x ∈ R, x ≤ x²
Four loan balances are $6,500, $3,600, $5,400, and $7,500, respectively. The current interest rates for the loans are 7%, 5%, 6%
My name is Ann [436]
[(455 + 180 + 324 + 675)/(65 + 36 + 54 + 75)] = 7.10
Answer is D.
