The total number of ways the study can be selected is: 637065
Given,
Total number of women in a group= 13
Total number of men in a group = 12
Number of women chosen = 8
Number of men chosen = 8
∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.
This in the form of combination factor = nCr
∴ nCr = n!/(n₋r)! r!
13C₈ = 13!/(13 ₋ 8)! 8!
= 13!/5!.8!
= 1287
12C₈ = 12!/(12₋8)! 8!
= 12!/5! 8!
= 495
Now multiply both the combinations of men and women
= 1287 × 495
= 637065
Hence the total number of ways the study group is selected is 637065
Learn more about "Permutations and Combinations" here-
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Answer: OPTION A
Step-by-step explanation:
The distance between any number is always positive so we should apply the absolute value.
The distance between numbers=number 1-number2 (or vise versa, and that is why we need absolute value)
In your question, the two numbers are 3/4 and 2. Applying to the expression above, the distance between two numbers should be |3/4-2| or |2-3/4|.
The only option in your case is |3/4-2| and this is it.
Hope this helps!! :)
Please let me know if you have any question
It would be 10 because 7000 can go into 70,000 10 times. You can you a calculator or look at the zeros take away the 3 zeros in 7000 and then 3 zeros in 70,000 making it 7 and 70 and 7 goes into 70 10 times as well. I hope this helps!
Short answer: No and yes.
Yes First.
If the lower right point (looks like an C perhaps or an F) and the middle point and the upper left point lie on the same line and if D the middle point and the upper right point lie n the the same line, then yes. You have angle side angle. The lower right angle is given as equal to the upper left angle. The angles at C are vertically opposite angles and they are equal and you have been given 2 enclosed sides that are equal.
No
If the points I've described are not on the same line, then the triangles are not congruent. If I can, I'll edit this a second time.
Please Note:
You have done something that looks a bit illegal to me. I wouldn't just trade pictures. It only costs you another 5 points to issue another question. I do think, however, that it is very clever. In answering about 1700 questions, I've never seen this done. That's commendable.
