Answer:
1. = 3√10 2. = 5 3. = 6√2
Step-by-step explanation:
Use <u>Intersecting Secant-Tangent Theorem</u>:
If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.
1. In this circle, DB is a tangent and DA is a secant. They intersect at point D.
So DB² = DC x DA
² = 5 x (5 + 13)
² = 90
= √90 = 3√10
2. In this circle, FE is a tangent and FH is a secant. They intersect at point F.
So FE² = FG x FH
10² = x 20
100 = 20
= 5
3. In this circle, NM is a tangent and NP is a secant. They intersect at point N.
So NM² = NO x NP
² = 4 x (4 + 14)
² = 72
= √72 = 6√2
Solution :
It is given that a large institution is preparing food menus which contains foods A as well as B.
Each lunch provides :
10 units of carbohydrates
6 units of fats
7 units of proteins
The food from A cost = $0.12 per ounce
And food from B cost = $0.08 per ounce
Objective function :
Constraints :
Domain :
Range :
5 is in the Ten thousandths place
Answer:
C. 14
Step-by-step explanation:
Add LM and MN
(3x + 5) + (4x + 7)
(4x + 3x) + (5 + 7)
7x + 12
As we know the total is 33
So,
7x + 12 = 33
Subtract 12 from 33, which gives me 21
Now,
7x = 21
To make x alone, divide both sides by 7, and then we will get x = 3
If x = 3
LM = 3x + 5
= (3*3) + 5
= 9 + 5
= 14
Answer:
because when Noah was 17 Diego was 43 so his is higher so his would be more upstraight than Noah's