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Aleks [24]
2 years ago
14

Factor completely x^2-4

Mathematics
2 answers:
umka2103 [35]2 years ago
3 0

Answer: (x + 2) (x - 2)

Step-by-step explanation:

Solnce55 [7]2 years ago
3 0

Answer:

(x + 2) (x - 2)

Step-by-step explanation:

Given the quadratic expression,  x² - 4:

Use the <u>Difference of squares</u> factoring formula:

u² - v² = (u + v)(u - v)

Determine what are possible factors that could have a product of -4:

Since -2 × 2 = -4, these can be used as factors.

Therefore, the factors of the quadratic expression, x² - 4 are:

(x + 2) (x - 2)

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3 years ago
One of the roots of the quadratic equation 4mnx^2 – 6m^2x – 6n^2x + 9mn = 0 (m, n ≠ 0) is a)-3m/2n b)3m/2n c)2m/3n d)-2m/3n
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Answer:

B.\ \frac{3m}{2n}

Step-by-step explanation:

Given

4mnx^2 - 6m^2x - 6n^2x + 9mn = 0\ (m, n \neq  0)

Required

Calculate one of the root of the equation

4mnx^2 - 6m^2x - 6n^2x + 9mn = 0

Factorize

2mx(2nx - 3m) -3n(2nx - 3m) = 0

(2mx - 3n)(2nx - 3m) = 0

Split equation

2mx - 3n = 0\ or\ 2nx - 3m = 0

Make x the subject of formula in both expressions

2mx = 3n\ or\ 2nx = 3m

x = \frac{3n}{2m}\ or\ x = \frac{3m}{2n}

<em>From the list of given options, one of the roots of the equation is</em> \frac{3m}{2n}

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