3x3-9+2 plz help i may ask

Write the equation of a sine or cosine function to describe the graph.

docker41 [41]

Answer:

$y = 3 \sin(2\pi \: x) + 3$

6 0

2 years ago

Question 5

DochEvi [55]

7383838hdueheheheueuwjhwwhjwiw82828182828

7 0

1 year ago

Use the four functions below for this question:

Jlenok [28]

Answer:

We have four functions:

For f(x) we have two points (-2,2) and (-1,-1)

we will use two point form which is:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

So, on substituting the values we get:

$y-2=\frac{-1-2}{-1-(-2)}(x-(-2))$

$y-2=\frac{-3}{x+2}$

$y=-3x-4$

So, f(x)=-3x-4

We have g(x)=3x-4

Now, we will from h(x) we have two points let initial point on monday is (0,4) and tuesday (1,1) again use two point form we get:

$y-4=-3(x-0)$

$\Rightarrow y=-3x+4$

So, h(x)= -3x+4

Now, we will form j(x) we have three points (2,10) , (-2,6) and (2,22)

We will use (-2,6) and (2,22) to find the function with two point form.

$y-6=\frac{22-6}{2+2}x+2)$

$\Rightarrow y=4x+14$

j(x)= 4x+14

To find the slope we will compare the given function with general equation which is y= mx +c; m is the slope

And to find y-intercept we will put x=0

f(x)=-3x-4

Slope is: -3

And y-intercept is: (0,-4)

g(x)=3x-4

Slope is: 3

And y-intercept is: (0,-4)

h(x)= -3x+4

Slope is: -3

And y-intercept is: (0,4)

j(x)= 4x+14

Slope is: 4

And y-intercept is: (0,14)

8 0

3 years ago

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A 500 cm piece of wire with a radius of 0.2 cm has a resistance of 0.025 ohm. Find an equation that relates these variables.

kirza4 [7]

Answer:

Step-by-step explanation:

7 0

3 years ago

Ella invested $2,700 in an account paying an interest rate of 5.4% compounded

Dmitry [639]

Answer:

The account will take 7 years to reach a value of $4,020

Step-by-step explanation:

Compound Interest

When it occurs interest in the next period is then earned on the principal sum plus previously accumulated interest.

The formula is:

$A=P\left(1+{\frac {r}{n}}\right)^{nt}$

Where:

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

Ella invested P=$2,700 in an account with an interest rate of r=5.4% (0.054) compounded monthly. Since there are 12 months in a year, n=12.

It will be calculated when will the account have a value of A=$4,020. Substituting all the values in the formula:

$4,020=2,700\left(1+{\frac {0.054}{12}}\right)^{12t}$

Calculating:

$4,020=2,700\left(1.0045)^{12t}$

Dividing by 2,700:

$\frac{4,020}{2,700}=\left(1.0045)^{12t}$

To solve this equation for t, we need to apply logarithms:

$\log\frac{4,020}{2,700}=\log\left(1.0045)^{12t}$

Applying the logarithm power rule:

$\displaystyle \log\frac{4,020}{2,700}=12t\log 1.0045$

Dividing by 12log 1.0045:

$\displaystyle t=\frac{\log\frac{4,020}{2,700}}{12\log 1.0045}$

Calculating:

t= 7.39 years

Rounding to the nearest year, the account will take 7 years to reach a value of $4,020

3 0

3 years ago

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