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antiseptic1488 [7]
3 years ago
8

What is an equation of a line perpendicular to 5x+8y=16 and passed through (-5,7)

Mathematics
1 answer:
Snezhnost [94]3 years ago
8 0

Answer:

8x - 5y = -75 or y = 1⅗x + 15

Step-by-step explanation:

5x + 8y = 16

-5x - 5x

_____________

8y = -5x + 16

___ ________

8 8

y = -⅝x + 2

↑

slope

Now, Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE <em>Rate</em><em> </em><em>of</em><em> </em><em>Changes</em><em> </em>[<em>Slopes</em>]:

-⅝ → 1⅗ [or 8⁄5]

7 = 1⅗[-5] + b

-8

15 = b

y = 1⅗x + 15 >> Perpendicular Line in <em>Slope-Intercept Form</em>

If wanted in <em>Standard</em><em> </em><em>Form</em>:

y = 1⅗x + 15

-1⅗x - 1⅗x

_____________

-1⅗x + y = 15 [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]

-5[-1⅗x + y = 15]

8x - 5y = -75 >> Perpendicular Line in <em>Standard Form</em>

I am joyous to assist you anytime.

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