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yaroslaw [1]
3 years ago
8

Hey lol:) how are you?

Mathematics
2 answers:
zysi [14]3 years ago
8 0
Good thanks for asking:)
adell [148]3 years ago
8 0
Not good I have a lot of work to do
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What is 8x over 2y ?
Nana76 [90]

Answer:

6 2/3.. i think

Step-by-step explanation:

hopefully u understand my messy handwriting

4 0
3 years ago
A long solenoid with radius r = 7 cm and n = 3,170 turns/m carries a current i = 6. 7 a. What is the magnitude of the magnetic f
kondaur [170]

The magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T

<h3>Magnetic field inside solenoid</h3>

The magnetic field inside the central area of the solenoid is given by B = μ₀ni where

  • μ₀ = permeability of free space = 4π × 10⁻⁷ Tm/A,
  • n = number of turns per unit length = 3,170 turns/m and
  • i = current in solenoid = 6.7 A

Since B = μ₀ni

Substituting the values of the variables into the equation, we have

B = μ₀ni

B = 4π × 10⁻⁷ Tm/A × 3,170 turns/m × 6.7 A

B = 4π × 10⁻⁷ Tm/A × 21239 A-turns/m

B = 84956π × 10⁻⁷ T

B = 266897.15 × 10⁻⁷ T

B = 0.026689715 T

B ≅ 0.0267 T

So, the magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T

Learn more about magnetic field inside a solenoid here:

brainly.com/question/25562052

6 0
2 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

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\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

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12. At noon the temperature was 30 degrees Celsius. At night it becomes 25 degrees Celsius. How
yawa3891 [41]

Answer:

5 degrees colder

Step-by-step explanation:

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6 0
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3 years ago
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