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Below are the choices the answer is E
A. It is an animal cell because starch is the energy storing molecule in animal cells.
<span>B. It is an animal cell because starch is responsible for protein synthesizing in animal cells. </span>
<span>C. It is a plant cell because starch is responsible for protein synthesizing in plant cells. </span>
<span>D. It is a plant cell because starch is responsible for cell building in plant cells. </span>
<span>E. It is a plant cell because starch is the energy storing molecule in plant cells.</span>
I would say c sorry if it’s wrong
For this case we have that by definition:
![PV = nRT](https://tex.z-dn.net/?f=PV%20%3D%20nRT)
Where,
- <em>P: Pressure
</em>
- <em>V: volume
</em>
- <em>n: number of moles
</em>
- <em>R: universes constant of gases
</em>
- <em>T: temperature
</em>
Since the pressure, the number of moles and the universal constant do not change, then the equation is reduced to:
![V = kT](https://tex.z-dn.net/?f=V%20%3D%20kT)
Rewriting we have:
![k = \frac {V} {T}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%20%7BV%7D%20%7BT%7D)
Matching state 1 and state 2, we have:
![\frac {V1} {T1} = \frac {V2} {T2}](https://tex.z-dn.net/?f=%5Cfrac%20%7BV1%7D%20%7BT1%7D%20%3D%20%5Cfrac%20%7BV2%7D%20%7BT2%7D)
Clearing the volume in state 2 we have:
![V2 = T2 (\frac {V1} {T1})](https://tex.z-dn.net/?f=V2%20%3D%20T2%20%28%5Cfrac%20%7BV1%7D%20%7BT1%7D%29)
Then, replacing values:
![V2 = (17+273) (\frac {61.3} {68+273})\\V2 = 52.13 mL](https://tex.z-dn.net/?f=V2%20%3D%20%2817%2B273%29%20%28%5Cfrac%20%7B61.3%7D%20%7B68%2B273%7D%29%5C%5CV2%20%3D%2052.13%20mL)
Rounding off we have:
![V2 = 52 mL](https://tex.z-dn.net/?f=V2%20%3D%2052%20mL)
Answer:
The volume of the gas at 17 ° C would be:
![V2 = 52 mL](https://tex.z-dn.net/?f=V2%20%3D%2052%20mL)
Option A
Answer:
PCl5 <-> PCl3 + Cl2
PCl5 decomposes into PCl3 and Cl2 according to the equation above. A pure sample of Pcl5 is placed in a rigid, evacuated 1.00 L container. The initial pressure of the PCl5 is 1.00 atm. The temperature is held constant until the PCl5 reaches equilibrium with its decomposition products. The figures below show the initial and equilibrium conditions of the system.
As the reaction progresses toward equilibrium, the rate of the forward reaction
A) increases until it becomes the same as the reverse reaction rate at equilibrium
B) stays constant before and after equilibrium is reached
C) decreases to become a constant nonzero rate at equilibrium
D) decreases to become zero at equilibrium
Explanation:
At equilibrium, both forward and backward reactions take place with constant speed.
The reaction will never cease.
Due to this reason chemical equilibrium is called dynamic in nature.
At equilibrium:
the rate of forward reaction = rate of backward reaction
As the reaction progresses toward equilibrium, the rate of the forward reaction decreases to become a constant nonzero rate at equilibrium.
Answer is option C).