Example #1 write the chemical formula for Calcium Oxide
Step 1
-Find the Atomic symbol of the metal and non-metal on the periodic table
CaO
Step 2
Find the charges for Calcium and Oxygen
which are Ca 2+ and O 2-
Step 3
Balance out the charges
They are already balanced out
Here´s the chemical formula for Calcium Oxide
CaO
Example 2 write the chemical formula for Aluminum Oxide
Step 1
-Find the Atomic symbol of the metal and non-metal on the periodic table
A
l
O
Step 2
Find the charges for Aluminum and Oxygen
Which are Al 3+ and O 2-
Step 3
Balance out the charges
You need 2 Aluminum and 3 Oxygen to balance the charges
Al 3+ O 2-
Al 3+ O 2-
= 6 + O 2-
= 6-
Step 4
If you need more then one element to balance out the charges you identify that by using subscripts
Heres your chemical formula for Aluminum Oxide
Answer:
Kc = 105062.5 at 298K
Explanation:
First of all, we state the equilibrium:
3O₂(g) ⇄ 2O₃(g)
We know data about equilibrium concentration of oxygen. We suppose 1 mol of oxygen at the begining. During the reaction, x moles have reacted.
As ratio is 2:3, we can determine how many moles of ozone have been produced.
(x . 2)/3
So we have the final concentration of oxygen, so, let's find out x
1 - x = 0.016 moles
x = 0.984 moles
Then, the [O₃] in equilibrium will be (0.984 . 2) /3 = 0.656.
We supose a volume of 1 L, so we have molar concentration to determine Kc. Let's state the expression for it:
Kc = [O₃]² / [O₂]³
Kc = 0.656² / 0.016³ → 105062.5
Answer:
Reverse the reaction
Explanation:
Reactions:
Overall:
As can be seen, in the overall reaction we have in the reactants like in the second reaction and in the products. The is in the first reaction but as a reactant so we need to reverse that reaction:
Combining:
It means it will only allow some to go through but not all.
The concentration of each of the individual ions in a 0750 M Ba(OH)2 solution is
[Ba2+] = 0.750 M
[OH-]= 1.50 M
<h3>
calculation</h3>
write the equation for dissociation
that is Ba(OH)2 (s)→ Ba2+(aq) + 2OH-(aq)
by use of mole ratio of Ba(OH)2 : Ba2+ which is 1: 1 the concentration of Ba2+ is therefore= 0.750M
by use of mole ratio of Ba(OH)2 : OH- which is 1:2 the concentration of OH- =0.750 M x2/1=1.50 M