Answer: A reaction which occurs when equivalent quantities of H" (or 
) and OH" are mixed is a neutralization reaction.
Explanation:
When acid and base chemically combine together to form sat and water then it is know as neutralization reaction.
An acidic substance gives hydrogen ions 
on dissociation and a basic substance gives hydroxide ions 
on dissociation.
For example, 
is a neutralization reaction where an acid and base are mixed together to form water.
No salt is formed as because here the reactants are not present as compounds.
In a hydrolysis reaction, water molecule(s) is added to the reactant molecules.
For example, 
Oxidation is the process of addition of oxygen to a molecule and removal of hydrogen.
Reduction is the process of addition of hydrogen in a compound and the removal of oxygen atom.
Therefore, we can conclude that reaction which occurs when equivalent quantities of H" (or ) and OH" are mixed is a neutralization reaction.
Answer:
Concept: Chemical Analysis
- You need to start by graphing the data and then analyzing it.
- We can see that the horse has a distance in meters of 980 at the end of the 10 seconds hence it is the fastest.
- The horse line has a linearly representation, while the alternate line has parabolic tendencies towards the end. The steeper line indicates a faster change in time or velocity which results in a greater distance traveled indicating that the horse is faster.
- *I have confidence you can graph that*
alpha decay is an emission of ₂⁴He
nucleus. If an element undergoes an alpha decay, the mass of the daughter
nucleus formed is reduced by 4 compared to mass of parent atom and atomic
number is reduced by 2 compared to atomic number of parent atom.
Let's assume that the parent atom is X, atomic number is z and mass number is A. Then the formed daughter nucleus, Y should have atomic number as z-2 and mass number as A-4.
The equation is
(z) (A)X → ₂⁴α + (z-2)(A-4)Y
Example:
₉₄²³⁹Pu → ₂⁴α + ₉₂<span>²³⁵U</span>
1. To solve this question, you need to equalize the mass of solute for both solution. The calculation would be:
mass of solute= volume*concentration
mass1=mass2
volume1 * concentration1 = volume2 * concentration2
volume1 * 0.7%= 2L *(1000ml/L) * 0.2%
volume1 = 2000ml * (0.2%/0.7%)
volume1= 571.429 ml
2. Since you already have the volume of stock needed, you just need to subtract it from the total solution volume to count the number of solvents needed.
new solution volume= stock volume + diluting solvent volume
2L * 2000ml/L = 571.429ml + diluting solvent volume
diluting solvent volume= 2000ml- 571.429 ml= 1428.571ml
