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Alchen [17]
3 years ago
14

patricia fixes computers. she charges her customers $35 per hour of work. patricia charged her most recent customer $210. use th

e on-screen keyboard to complete the equation that can be used to find h, the number of hours patricia worked for her most recent customer. then, enter the number of hours she worked in the second box.
Mathematics
1 answer:
schepotkina [342]3 years ago
4 0
Patricia worked 6 hours on her last customer
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Assume that random guesses are made for seven multiple choice questions on an SAT test, so that there are n=7 trials, each with
Vedmedyk [2.9K]

Answer:

P(X < 4) = 0.5

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this question, we have that:

n = 7, p = 0.5

Find the probability that the number of correct answers is fewer than 4:

This is

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{7,0}.(0.5)^{0}.(0.5)^{7} = 0.0078

P(X = 1) = C_{7,1}.(0.5)^{1}.(0.5)^{6} = 0.0547

P(X = 2) = C_{7,2}.(0.5)^{2}.(0.5)^{5} = 0.1641

P(X = 3) = C_{7,3}.(0.5)^{3}.(0.5)^{4} = 0.2734

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0078 + 0.0547 + 0.1641 + 0.2734 = 0.5

So

P(X < 4) = 0.5

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