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makvit [3.9K]
3 years ago
14

If a rectangle is quadrilateral with four right angles then what is the sum of its interior angles?

Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0
(4-2)×180°=360°
the sum of the rectangle is 360°
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A rectangle with a perimeter of 19m^2+2m-10 and a width of m^2 write an expression for the lenght
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Answer:

8.5m^{2}+ m -5

Step-by-step explanation:

Since perimeter, P=19m^{2}+ 2m -10 and we know that P=2(l+w) then P=2(l+m^{2})=2l+2m^{2}

The length will be 2l=19m^{2}+ 2m -10-2m^{2}=17m^{2}+ 2m -10

Now l=8.5m^{2}+ m -5

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2 years ago
A maritime flag is shown. What is the area of the shaded part of the flag? Explain
Rom4ik [11]

Answer:

<em></em>Area = 72in^2<em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate  the Area:</em>

<em></em>Area_1 = Length * Width<em></em>

<em></em>Area_2 = 8in * (6in + 6in)<em></em>

<em></em>Area_2 = 8in * 12in<em></em>

<em></em>Area_1 = 96in^2<em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em>Area_2 = \frac{1}{2} * base * height<em></em>

<em></em>Area_2 = \frac{1}{2} * (6in + 6in) * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 12in * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 48in^2<em></em>

<em></em>Area_2 = 24in^2<em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em>Area = Area_1 - Area_2<em></em>

<em></em>Area = 96in^2 - 24in^2<em></em>

<em></em>Area = 72in^2<em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0
2 years ago
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