<h3>
Answer: -35</h3>
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Explanation:
Let y = -3*f(-3) + 2*f(3)
The goal is to find the value of y as some single numeric value.
We know that f(x) is an odd function. This means that
f(-x) = -f(x)
For all x in the domain of f(x).
Based on that, we can say
f(-3) = -f(3)
and,
y = -3*f(-3) + 2f(3)
-1*y = -1*(-3*f(-3) + 2*f(3)) ... multiply both sides by -1
-y = 3*f(-3) - 2*f(3)
-y = 3*f(-3) + 2*(-f(3))
-y = 3*f(-3) + 2*f(-3)
-y = 3*7 + 2*7 .... f(-3) replaced with 7
-y = 21+14
-y = 35
y = -35
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Here's a slightly different approach
f(-3) = 7
-f(3) = 7
Since f(-3) = -f(3)
We can then transform -f(3) = 7 into f(3) = -7 after multiplying both sides by -1
Therefore,
y = -3*f(-3) + 2f(3)
y = -3*7 + 2(-7)
y = -21 - 14
y = -35
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There are probably other routes to solve this problem.
Whichever path you take, you should find that -3*f(-3) + 2f(3) = -35
Answer:
256 burgers
Step-by-step explanation:
64 ÷ ¼
64 × 4
256
Yes. B/c as long as it has the same variable, you can add them, subtract, or anything else to them. As long as they have the same variable in common.
Hope this helps (:
Numerical expressions use numbers and algebraic expressions use variables.
Answer:
(14a + 3, 21a + 4) = 1
Step-by-step explanation:
Step-by-step explanation:
To prove that the greatest common divisor of two numbers is 1, we use the Euclidean algorithm.
1. In this case, and applying the algorithm we would have:
(14a + 3, 21a + 4) = (14a + 3, 7a + 1) = (1, 7a + 1) = 1
2. Other way of proving this statement would be that we will need to find two integers x and y such that 1 = (14a + 3) x + (21a + 4) y
Let's make x = 3 and y = -2
![(14a+3)(3) + (21a+4)(-2)\\42a+9-42a-8\\1](https://tex.z-dn.net/?f=%2814a%2B3%29%283%29%20%2B%20%2821a%2B4%29%28-2%29%5C%5C42a%2B9-42a-8%5C%5C1)
Therefore, (14a + 3, 21a + 4) = 1