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3 years ago

I NEED HELP ASAP

Mathematics

2 answers:

mafiozo [28]3 years ago

7 0

Answer:

Help I need HELP FAST I give brainliest.

IGNORE THIS TEXT: Which graph shows this solution set? y is greater than negative 2 and y is less than or equal to 2Answer options with 5 optionsA.The graph shows a number line.Short description, The graph shows a number line.,Long description,A number line has negative 2 and positive 2. At negative 2 and positive 2, there are filled in circles. Between negative 2 and positive 2, the number line is shaded. B.The graph shows a number line.Short description, The graph shows a number line.,Long description,A number line has negative 2 and positive 2. At negative 2 and positive 2, there are open circles. Between negative 2 and positive 2, the number line is shaded. C.The graph shows a number line.Short description, The graph shows a number line.,Long description,A number line has negative 2 and positive 2. At negative 2, there is an open circle. At positive 2, there is a filled-in circle. Between negative 2 and positive 2, the number line is shaded. D.The graph shows a number line.Short description, The graph shows a number line.,Long description,A number line has negative 2 and positive 2. At negative 2, there is an open circle. At positive 2, there is a filled-in circle. The number line is shaded to the left of negative 2 and to the right of positive 2. E.The graph shows a number line.Short description, The graph shows a number line.,Long description,A number line has negative 2 and positive 2. At negative 2, there is filled in circle. At positive 2, there is an open circle. The number line is shaded to the left of negative 2 and to the right of positive 2.

kvasek [131]3 years ago

6 0

Answer:

He would be paying 625 extra if he paid monthly.

Step-by-step explanation:

143.75 x 12(5) = 8,625.

You might be interested in

if an exterior angle of a regular polygon measures 15 degrees how many sides does it have ?a.23. b.24. c.25

dimaraw [331]

Answer:

B.24

Step-by-step explanation:

we know,

exterior angle = 360°/n(where 'n' is number of sides)

then,

15° = 360°/n

n = 360°/15°

n = 24

3 0

3 years ago

Help with a,b,c answers

Ket [755]

The answers For A,B,C.
A.2
B.2.25
C.1

6 0

3 years ago

Justin made 184 for 8 hours of work. At the same rate, how many hours would he have to work to make 115?

Kisachek [45]

Answer:

8/184

0.0434782609x115

Step-by-step explanation:

7 0

3 years ago

Ricky withdrew a total of $175 from his bank account over 5 days. He withdrew the same amount each day. By how much did the amou

kifflom [539]

Answer:

$35

Step-by-step explanation:

175/5 = 35

have a nice day! (maybe get this double checked in case I did it wrong :D)

8 0

2 years ago

Mystery Boxes: Breakout Rooms

ollegr [7]

Answer:

$\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}$

Step-by-step explanation:

Given

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {[ \ ]} \\ \end{array}$

Required

Fill in the box

From the question, the range is:

$Range = 60$

Range is calculated as:

$Range = Highest - Least$

From the box, we have:

$Least = 1$

So:

$60 = Highest - 1$

$Highest = 60 +1$

$Highest = 61$

The box, becomes:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

From the question:

$IQR = 20$ --- interquartile range

This is calculated as:

$IQR = Q_3 - Q_1$

$Q_3$ is the median of the upper half while $Q_1$ is the median of the lower half.

So, we need to split the given boxes into two equal halves (7 each)

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } \\ \end{array}$

Upper half

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

The quartile is calculated by calculating the median for each of the above halves is calculated as:

$Median = \frac{N + 1}{2}th$

Where N = 7

So, we have:

$Median = \frac{7 + 1}{2}th = \frac{8}{2}th = 4th$

So,

$Q_3$ = 4th item of the upper halves

$Q_1$ = 4th item of the lower halves

From the upper halves

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

We have:

$Q_3 = 32$

$Q_1$ can not be determined from the lower halves because the 4th item is missing.

So, we make use of:

$IQR = Q_3 - Q_1$

Where $Q_3 = 32$ and $IQR = 20$

So:

$20 = 32 - Q_1$

$Q_1 = 32 - 20$

$Q_1 = 12$

So, the lower half becomes:

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {12 } & {15} & {18}& {[ \ ] } \\ \end{array}$

From this, the updated values of the box is:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$