Answer:
1) C. 2
2) A. 2
Step-by-step explanation:
1. We need to descompose 256 into its prime factors:
We must rewrite the expression ![\sqrt[8]{256}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B256%7D)
:
![=\sqrt[8]{2^8}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B8%5D%7B2%5E8%7D)
We need to remember that:
![\sqrt[n]{a^n}=a](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da)
Then:
2. Let's descompose 16 into its prime factors:
We must rewrite the expression ![\sqrt[4]{16}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D)
:
![=\sqrt[4]{2^4}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B4%5D%7B2%5E4%7D)
Then we get:
Answer:
The 3rd one as it's cubic
Answer: 345.02
Step-by-step explanation:
Answer:
3/7
Step-by-step explanation:
The number of possible results are;
1, 2 , 3 , 4 , 5, 6 , 7 = 7
odd numbers here are;
1, 3 , 5 and 7
non-odd numbers are 2, 4 and 6
So the section not labeled with an odd number is 3
Hence the probability here is that;
3/7
