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nordsb [41]
3 years ago
9

During a scuba dive, Lainey descended to a point 29 feet below the ocean surface. She continued her descent at a rate of 29 feet

per minute. Enter an inequality you could solve to find the number of minutes she can continue to descend if she does not want to reach a point more than 81 feet below the ocean surface. Use t to represent the variable for the minutes Lainey can continue to descend.
Mathematics
1 answer:
Alex73 [517]3 years ago
6 0

Answer:

Her initial position was:

-29ft

Where we use the minus sign because this is below the ocean's surface.

Now we also know that she keeps descending at a rate of -29ft per minute, then if she keeps descending for t minutes, her position will be:

P(x) = -29ft - 29ft/min*t

Now, we also know that she does not want to descend more than 81ft below the ocean's surface, then we have the inequality:

P(x) ≥ -81ft

-29ft - 29ft/min*t ≥ -81ft

Now let's isolate t in one side:

- 29ft/min*t ≥ -81ft + 29ft = -52 ft

- 29ft/min*t ≥-52 ft

                t ≤ -52ft/(- 29ft/min) = 1.79 min

Then the maximum amount of time that she can keep descending is 1.79 minutes.

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H = 151t - 16t²

The height of the ball when it return to the ground will be 0
0 = 151t - 16t²

The zero product property is that when two numbers are being multiplied and the product is 0, one of them must be equal to 0. Therefore, we can factorize this equation:
16t² - 151t = 0
t(16t - 151t) = 0
By the zero product property:
t = 0   or  16t - 151 = 0

So t = 0 or t = 9.44 seconds

The first solution is before he releases the ball and the second is when the ball comes back to the ground. Thus, the ball's air time is 9.44 seconds.
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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