The average speed of Ken is 70 m/min. Using the relation between the speed and distance, the required speed for Ken is calculated.
<h3>What is the relation between speed and distance?</h3>
The relationship between speed S and distance D with a period T is formed as
S = D/T
Units: m/sec (basic unit)
<h3>Calculation:</h3>
Given that,
Jaylen and Ken started jogging from the same place in opposite directions along a straight path.
This means, that the sum of distances traveled by both of them in opposite directions = 13.6 km (since it is given that at the end of their jogging, they are 13.6 km apart)
Consider,
The distance traveled by Jaylen = x km
Then the distance traveled by Ken = x - 2.4 km (since Jaylen jogged 2.4 km more than Ken)
Step 1: Finding the distance traveled by them:
x + x - 2.4 = 13.6
⇒ 2x = 13.6 + 2.4
⇒ 2x = 16
⇒ x = 8 km
So, the distance travelled by Jaylen = 8 km and by Ken = 8 - 2.4 = 5.6 km
Step 2: Finding the average speed traveled by Ken:
Since it is given that,
Jaylen's speed was 30 m/min faster than Ken's speed.
So,
For 30 m, the time = 1 min
then for 2.4 km i.e., 2400 m, the time = 80 min.
Therefore,
the average speed of Ken S = D/t
⇒ S = 5600 m / 80 min
∴ S = 70 m/min.
So, the average speed of Jaylen will be 70 m/min + 30 m/min = 100 m/min.
Thus, the average speed of Ken is 70 m/min.
Learn more about the relation between speed, distance, and time here:
brainly.com/question/3004254
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