Question

Using the quadratic formula, which of the following is the solution to the

Answer 1

Answer:

${x}^{2} - 6x + 11 = 0 \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{6± \sqrt{ - 8} }{2} \\ x = \frac{6±2i \sqrt{2} }{2} \\ x = 3±i \sqrt{2}$

Answer 2

Answer:

$x=3\pm\sqrt{2}i$

Step-by-step explanation:

$x^2-6x+11=0$

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-6)\pm\sqrt{(-6)^2-4(1)(11)} }{2(1)}$

$x=\frac{6\pm\sqrt{36-44} }{2}$

$x=\frac{6\pm\sqrt{-8} }{2}$

$x=\frac{6\pm2\sqrt{2}i }{2}$

$x=3\pm\sqrt{2}i$