|-3|=3 right?
Then it is
3*-6=-18
Answer:
Randomized block design
Step-by-step explanation:
From the question, we can see the following:
- There are 30 plants of each variety. This means that they are divided into variety subgroups which we will call blocks.
- Now, we are told each plant in each block all are potted in the same amount and type of soil, given the same amount of water, and exposed to the same amount of light. This means that each plant in each block is assigned a treatment condition.
- The procedure is repeated by subjecting each plant one after the other in teach Block to different treatments and this will reduce variability.
Looking at all the statements above, it is clear that this is a randomized block design because a randomized block design is when the experimenter/researcher divides members/participants into subgroups called blocks in a manner that the variability within the blocks is less than the variability between the blocks. Thereafter, the participants within each block will now be randomly assigned to treatment conditions.
Answer:
The correct answer is
(x + 2) (x + 1) (x - 3)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
Answer:
Step-by-step explanation:
Consider the options for this question are as follow,
Here, In triangles ABC and PQR,
AB = c, BC = a, AC = b, PQ = r, QR = p and PR = q,
Since,
We know that,
The corresponding sides of similar triangles are in same proportion,
Thus,