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Alenkasestr [34]
3 years ago
5

A furnace operates at 2,300°F.

Mathematics
1 answer:
Cloud [144]3 years ago
6 0

Answer:

T = 2,300 + q × 250

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Pls answer if u do know
stepladder [879]

C √18

............

............

............

............

5 0
3 years ago
Read 2 more answers
Find the limit. use l'hospital's rule if appropriate. if there is a more elementary method, consider using it. lim x→1 1 − x + l
AfilCa [17]

\displaystyle\lim_{x\to1}\frac{1-x+\ln x}{1+\cos5\pi x}

Evaluating the limand directly at x=1 gives an indeterminate form \dfrac00. Apply L'Hospital's rule once and we get

\displaystyle\lim_{x\to1}\frac{-1+\frac1x}{-5\pi\sin5\pi x}

Again, plugging in x=1 returns \dfrac00. Apply the rule once more:

\displaystyle\lim_{x\to1}\frac{-\frac1{x^2}}{-25\pi^2\cos5\pi x}=\frac1{25\pi^2}\lim_{x\to1}\frac1{x^2\cos5\pi x}

Now, in the denominator, when x=1 we get x^2\cos5\pi x=-1, so the limit is -\dfrac1{25\pi^2}.

3 0
3 years ago
Answer this question I need help as soon as possible
torisob [31]

Answer

Because the function says 1.045 means 1+0.045

0.045=4.5%

So your answer is

4.50%

6 0
3 years ago
Find the area and perimeter of the room.. the vertices are 10,20 -10,20 -10,-10 10,-10
Ierofanga [76]
The numbers in this problem are ordered pairs, which are points on a graph.
These are (10, 20), (-10, 20), (-10, -10), and (10, -10).
To find the area and perimeter of this shape, you must first find the distance between each point.

Distance between (10, 20) and (-10, 20):
Since the y-value remains the same here, we just have to find the difference in x-values.
This means 10 - (-10)
A negative being subtracted is the same as a positive being added.
That means 10 - (-10) is the same as 10 + 10.
10 + 10 = 20, so the distance between (10, 20) and (-10, 20) is 20 units.

Distance between (-10, 20) and (-10, -10):
The x-values are the same here so just find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between the (-10, 20) and (-10, -10) is 30 units.

Distance between (-10, -10) and (10, -10):
The y-values are the same so just find the difference between the x-values.
10 - (-10) = 10 + 10 = 20
The distance between (-10, -10) and (10, -10) is 20 units.

Distance between (10, -10) and (10, 20):
The x-values are the same so find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between (10, -10) and (10, 20) is 30 units.

So now we know the side lengths of the room are 20 units, 30 units, 20 units, and 30 units.

To find the perimeter, add all the side lengths together.
20 + 30 + 20 + 30 = 100
The perimeter of the room is 100 units.

To find the area, multiply the length by the width.
The length is 20 units and the width is 30 units.
20 • 30 = 600
The area of the room is 600 units.

Final answers:
Perimeter = 100
Area = 600

Hope this helps!
7 0
3 years ago
16 POINTS. Find x and y intercepts and show work. <br><br> I’m looking for number six.
aliya0001 [1]
X^4-3x³+4x
x^4-3x³+3x+x
(x^4+x)-(3x³-3x)
x(x³+1)-3x(x²-1)
x(x+1)(x²-x+1)-3x(x+1)(x-1)
x(x+1)(x²-x+1-3x+3)
x(x+1)(x²-4x+4)
x(x+1)(x-2)(x-2)
so x intercepts are (0,0), (-1,0) and (2,0)
the y intercept is (0,0)

8 0
3 years ago
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