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kicyunya [14]
3 years ago
8

A car traveled 180 miles at a constant rate. Write an equation that would

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

180/t = r

Step-by-step explanation:

In this question, we would have to write an equation that represents the scenario given.

We know that the car traveled 180 miles at a constant rate.

We would use the y = mx + b format for the equation, but replacing the variables with "r" and "t"

We know that 180 will be our y-variable, since that would be the base of the equation:

180 = ???

And to find how long/fast it will take the car, we would need to multiply the rate of speed "r" and time "t" in order to get our distance.

Plug it into the equation:

180 = rt

With this set up, you can find the rate of speed of the car when you know the time.

You would simply solve it as:

180/t = r

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A population has mean 187 and standard deviation 32. If a random sample of 64 observations is selected at random from this popul
Zina [86]

Answer:

11.51% probability that the sample average will be less than 182

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 187, \sigma = 32, n = 64, s = \frac{32}{\sqrt{64}} = 4

What is the probability that the sample average will be less than 182

This is the pvalue of Z when X = 182. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{182 - 187}{4}

Z = -1.2

Z = -1.2 has a pvalue of 0.1151

11.51% probability that the sample average will be less than 182

8 0
3 years ago
X/3+9=17 simplify your answer
frosja888 [35]
I think the answer might be x=24
8 0
3 years ago
Solve: s = 4 + √ s + 2<br><br> a. s=2<br> b. s=7<br> c. s=2 or s=7<br> d. no real solution
lyudmila [28]

Rewrite s = 4 + sqrt(s+2) as s-4 = sqrt(s+2)


Square both sides: s^2 - 8s + 16 = s + 2


combine like terms: s^2 - 9s + 14 = 0


Factor this: (s-7)(s-2)=0


Solve for s: s={7, 2}

4 0
4 years ago
Read 2 more answers
Which graph shows three points that represent equivalent ratios?<br> hurry plz
pshichka [43]

Answer:

it will be c because you see the points on the grid if its wrong my bad

Step-by-step explanation:

3 0
3 years ago
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Use base ten blocks to find 182 ÷14 describe the steps you took to find your answer
docker41 [41]
It would be 
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