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Natali5045456 [20]
3 years ago
13

7th grade math plz help

Mathematics
1 answer:
mina [271]3 years ago
7 0

Answer:

x = 3

y = 3/2

Step-by-step explanation:

look at the hangers to form an equation:

x + x + x + 3 + 3 + 3 = x + x + y + y + y + y

simplify

3x + 3 = 2x + 4y

x + 3 = 4y

x = 4y - 3

you also know that

x + x = y + y + y + y

2x = 4y

substitute x = 4y - 3 into this equation ^

2x = 4y

2(4y - 3) = 4y

8y - 6 = 4y

4y = 6

y = 6/4

y = 3/2

2x = 4y

2x = 12/2

2x = 6

x = 3

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The following graph shows a bus’s record of the number of passengers it picked up over the course of a day. A bar graph titled B
Setler [38]

Answer:

(A)55

Step-by-step explanation:

\left|\begin{array}{c|ccccccccccccccc}x(Time)&7&8&9&10&11&12&1&2&3&4&5&6\\y(Passsengers)&40&62&58&43&36&55&41&28&31&37&75&64\end{array}\right|

From the values on the graph which is presented in the table above, the number of people who rode the bus during the 12.00 hour is 55.

<u>The correct option is A.</u>

7 0
3 years ago
Read 2 more answers
On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

d_1 - 20 = 60t_1 - 120

d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

d_1 = 200

Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0
3 years ago
1. r-8/5=-4/11<br> 2. 9a/a+4= 3/5
BigorU [14]

Answer:

1 r= 68/55

2 no solution

Step-by-step explanation:

3 0
3 years ago
Help me please I beg
valentina_108 [34]

Answer:

$8,500

Step-by-step explanation:

Interest = 5000 x 5 x 0.14

            = 1000 x 0.14 x 25

            = 140 x 25

            = 3500

5000 + 3500 = 8500

8 0
2 years ago
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Gemiola [76]
I pretty sure it is A. but please someone check behind me
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3 years ago
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