Answer: The answer is 27
Given:
- Mr. Roberts will drive 56 miles
- He has 29 more miles to go
We will:
Subtract the total distance he plants to travel by the amount he has left.
<em> Equation: </em>
Our answer is 27. Best of Luck!
HELP ASAP !!! The table shows several points for function j(t).
2 answers:
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Answer:
And if we solve for a we got;
So the value of height that separates the bottom 95% of data from the top 5% is 11.64
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent certain lifetime of a population, and for this case we know the distribution for X is given by:
Where and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
Both conditions are equivalent on this case. We can use the z score again in order to find the value a.
As we can see on the figure attached the z value that satisfy the condition with 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64. On this case P(Z<1.64)=0.95 and P(z>1.64)=0.05
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got;
So the value of height that separates the bottom 95% of data from the top 5% is 11.64
The imaginary unit belongs to the set of complex numbers, denoted by
. These numbers take the form
, where
are any real numbers.
The set of real numbers, , is a subset of
, where each number in
can be obtained by taking
and letting
be any real number.
But any number in with non-zero imaginary part is not a real number. This includes
.
- "is it possible that i can use an imaginary number for a real number"
I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because .
There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising to the
-th power. Since
, we have