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2 years ago

HELP ASAP !!! The table shows several points for function j(t).

Mathematics

2 answers:

worty [1.4K]2 years ago

8 0

Answer:

Step-by-step explanation:

max2010maxim [7]2 years ago

4 0

Answer:

d on edge

Step-by-step explanation:

its just the table flipped

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Which data set represents the histogram?

madam [21]

The answer is B because it includes all of the numbers correctly

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2 years ago

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Point A is at (-1, -9) and point M is at (0.5, -2.5).

vladimir2022 [97]

Answer:

Point B is located at point (2, 4)

Step-by-step explanation:

Since point M is at the center, you find the distance from point A and add that to the other side.

| -1 - 0.5 | = | -1.5 | = 1.5

| -9 - -2.5 | = | -6.5 | = 6.5

Now we can add that to point M to find point B

0.5 + 1.5 = 2

-2.5 + 6.5 = 4

Point B should be at (2, 4)

4 0

3 years ago

Tamara has two sisters. one of the sisters is 7 years older than Tamara. The other sister is 3 years younger than Tamara. the pr

fenix001 [56]

Answer:

Step-by-step explanation:

24=x+(x-3)+(x+7)

7 0

3 years ago

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2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0

3 years ago

How do you do the equation 2 to the second power over 2 to the 3rd power

padilas [110]

2 to the second power is 2 x 2 (4) , and 2 to the 3rd power is 2 x 2 x 2 (8)

3 0

3 years ago

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