Answer:
<h2>
<em><u>The answer is: 18</u></em></h2>
<em><u>Hope this helps you! </u></em><em><u>.</u></em>
Answer:
I dopnt know
Step-by-step explanation:
Im asking the same question lol
Answer:
C. 1/(x^2 +1) > 0
Step-by-step explanation:
The cube of a negative number is negative, eliminating choices B and D for certain negative values of x.
1/x^2 is undefined for x=0, so cannot be compared to zero.
The value 1/(x^2+1) is positive everywhere, so that is the expression you're looking for.
1/(x^2 +1) > 0
I am not sure but wouldn't it be y=3x-6 and y=4x-7
