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Alexandra [31]
2 years ago
10

8. A peacock weighs 152 ounces.How many pounds does the peacock weight?

Mathematics
1 answer:
natita [175]2 years ago
3 0

Answer:

10

Step-by-step explanation:

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State all integer values of x in the interval [0,7] that satisfy the following inequality
Anestetic [448]

Answer:

x>3/2

Step-by-step explanation:

3 0
3 years ago
The following formula relates 3 equantities: force(F),mass(m),and acceleration(a)
weqwewe [10]
We know, Force = mass × acceleration


( i ) :

Given,
Force = 25 units
Mass = 10 units
Acceleration = ?


Solution,

Applying the formula of force,
➡ Force = mass × Acceleration

⏩ 25 = 10 × acceleration

⏩ 25 / 10 =acceleration

⏩ 2.5 units = acceleration




( ii ) :


Given,
Force = 25 units
Acceleration = 5 units
Mass =?



Solution :

Applying formula,
➡ Force = mass × acceleration

⏩ 25 = 5 × mass

⏩ 25 / 5 = mass

⏩ 5 units = mass



\:
5 0
2 years ago
-2x - y =0 is it direct variation?​
oksian1 [2.3K]

Answer:

y=11

Step-by-step explanation:

4 0
2 years ago
How many diagonals can be constructed from one vertex of an n-gon? State your answer in terms of n and, of course, justify your
natulia [17]

Answer:

The \ total \ number \ of \ distinct \ diagonals \ in \ a \ polygon \ with \ n \ sides= \dfrac{n \times (n - 3)}{2}

Step-by-step explanation:

A diagonal is defined in geometry as a line connecting to two non adjacent  vertices.

Therefore, the minimum number of sides a polygon must have in order to have a diagonal n - 3 sides as the 3 comes from the originating vertex and the other two adjacent vertices

Given that the polygon has n sides, the number of diagonals that can be drawn from each of those n sides gives the total number of diagonals as follows;

Total possible diagonals = n × (n - 3)

However, half of the diagonals drawn within the polygon are the same diagonals drawn in reverse. Therefore, the total number of distinct diagonals that can be drawn in a polygon is given as follows;

The \ total \ number \ of \ distinct \ diagonals \ in \ a \ polygon \ with \ n \ sides= \dfrac{n \times (n - 3)}{2}

6 0
3 years ago
En france en 1900 la taille moyennes des femmes etait de 1,54 m et celle des hommes de 1,66 m. Entre 1900 et 2010 ces tailles mo
frez [133]

Complete question :

En France, en 1900, la taille moyenne des femmes était de 1,54 m et celle des hommes de 1,66 m. Entre

1900 et 2010 ces tailles moyennes ont augmentées d'environ 5,55%.

Calculer, en mètres, l'arrondi au centième des tailles moyennes des femmes et des hommes en 2010.​

Répondre :

Femmes = 1,63

Hommes = 1,75 m

Explication étape par étape:

Étant donné que :

Taille moyenne en 1900:

Hommes = 1,66 m

Femmes = 1,54 m

Pourcentage d'augmentation de poids d'ici 2010 = 5,55%

1 + 5,55% = 1 + 0,0555 = 1,0555

D'où,

Taille des femmes en 2010:

1,0555 * 1,54 = 1,62547 = 1,63 m

Pour la taille des hommes en 2010:

1,0555 * 1,66 m = 1,75213 = 1,75 m

3 0
3 years ago
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