Answer:
11 memberships
Step-by-step:
Gym 1 = 75+5m
Gym 2 = 50+7.5m
75+5m=50+7.5m
-50 from both sides
25+5m=7.5m
-5m from both sides
25=2.5m
divide both sides by 2.5
10=m
for 10therefor 75+5m<50+7.5m he must sell 11 memberships.
20 ÷ 5 = 4
So there are 4 sets of 5 shirts. If there are 3 striped shirts per 5 then
3 x 4 = 12 striped shirts
Hope it helps!
<h2>
Hello!</h2>
The answer is:

<h2>
Why?</h2>
A multiple of a number is the repeated sum of itself, for example:
Multiple of the number 1 are: 1, 2, 3, 4, 5 and so...
Multiple of the number 3 are: 3, 6, 9, 12, 15 and so...
From the example we have:
Multiple of the number 3 are: Itself, (3+3), (3+3+3), (3+3+3+3), (3+3+3+3+3) and so...
So,
Multiple of
are:

Have a nice day!
Answer:
See explanation
Step-by-step explanation:
Consider triangles CAX and BAX. In these triangles,
- given
- given
- reflexive property
By SAS postulate, 
Congruent triangles have conruent corresponding parts. So,

Consider triangles CXY and BXY. In these triangles,
- proven
- given
- reflexive property
By SAS postulate, 
Congruent triangles have conruent corresponding parts. So,
