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2 years ago

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Mathematics

1 answer:

Flauer [41]2 years ago

6 0

Answer:

what is the question?

Step-by-step explanation:

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What is 13.8÷10 and a half

KengaRu [80]

The answer is 1.314

hope it helps

8 0

2 years ago

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What is an equation of the line that passes through the point (−3,−1) and is perpendicular to the line x-2y=6?

gogolik [260]

Answer:

y = 2x+5

Step-by-step explanation:

rearrange the equation to make y the sof

y = 1/2x - 3

to find gradient of perpendicular line

1/2 ÷ ( - 1 )

y = -2x + c , the replace the coordinates (-3,-1)

y = 2x + 5

5 0

2 years ago

Which statement is true for the equation 4n – 3 = 4n – 2 Select one: a. It has no solution. b. It has one solution. c. It has tw

oksian1 [2.3K]

4n-3=4n-2 subtract 4n from both sides

-3=-2

Since -3!=-2, there is no solution.

So your answer is a.

7 0

3 years ago

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Solve Ax + By = C for x.

Zolol [24]

Answer:

the first option

Step-by-step explanation:

Given

Ax + By = C ( subtract By from both sides )

Ax = C - By ( divide both sides by A )

x = $\frac{C-By}{A}$

7 0

3 years ago

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz. An ornithologi

il63 [147K]

Answer:

The formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.7}{2} = 0.15$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.15 = 0.85$ , so Z = 1.037.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz.

This means that $\sigma = 0.04$ .

Sample of 10 birds:

This means that $n = 10$ .

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.037\frac{0.04}{\sqrt{10}}$

$M = 0.013$

The lower end of the interval is the sample mean of $\overline{x}$ subtracted by M.

The upper end of the interval is the sample mean of $\overline{x}$ added to M.

Then, the formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

8 0

3 years ago