Answer:
21.19% eat less than 10 pieces of candy on halloween
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What percentage eat less than 10 pieces of candy on halloween
This is the pvalue of Z when X = 10.
has a pvalue of 0.2119
21.19% eat less than 10 pieces of candy on halloween
Well 8 times 4 is 32 so he bought 32 strawberries
don’t know if this is what you were looking for but hope it helps
First we need to find the common ratio by dividing the second term by the first term. 36/120 = 3/10
an = a1 * r^(n-1)
n = term to find = 5
a1 = first term = 120
r = common ratio = 3/10
now we sub and solve
a5 = 120 * 3/10^(5 - 1)
a5 = 120 * 3/10^4
a5 = 120 * .0081
a5 = 0.972 <=== fifth term
or we could have just done this......since we multiply by 3/10 to find the next number...
a3 = 10.8......10.8 * 3/10 = 3.24 <== 4th term
3.24 * 3/10 = 0.972 <== fifth term
Answer:
Step-by-step explanation:
The data plots represent the hours students study each week in two different classrooms.
The mean number of hours a student in Mr. Hart’s class studies is <em>4.6</em> hours.
The mean number of hours a student in Ms. Perry’s class studies is <em>2.8</em> hours.
A typical student in Mr. Hart’s class studies <em>More Than</em> a typical student in Ms. Perry’s class.
<em>I Hope This Helps !!! </em>
<em>\(⇀v↼)/</em>
Answer:
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