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3 years ago

I need help please. Also check out my other question

Mathematics

1 answer:

siniylev [52]3 years ago

5 0

Answer:

Explanation:

I'm going to turn the fractions into decimals

2 ½: 2.5

3 ⅕: 3.2

Formula for the area of a parallelogram: A = b(h)

Base: 3.2

Height: 2.5

3.2 · 2.5 = 8

<h3><u>The area of the parallelogram is 8 Km.</u></h3>

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I need help I have the answer just need the top part

algol13

Answer:

24 = 60 x 0.4 or 24 = 60 x 40%

Step-by-step explanation:

24 / 0.4 = 60 so 24 = 60 x 0.4

8 0

3 years ago

Read 2 more answers

A little help please. THANK YOU

Natasha2012 [34]

I think it is D) because the 2x is really the x-axis. But im not sure... A and B are crossed out bc there negatives. Sooo.. its C or D.

7 0

4 years ago

Percent of change from 115 to 338

MrRa [10]

Answer:

237 ⁹/23% change

Step-by-step explanation:

115=100%

337-155=273 which represents the increase

115=100

273=?

273×100÷115= 237 ⁹/23%

Answer =237⁹/23%

7 0

3 years ago

a submarine is 100 meters below sea level when it begins to ascend at a steady rate of 3.0 miles per minute interpret values wha

Angelina_Jolie [31]

Answer:

y = 3x - 100

Step-by-step explanation:

below signifies that the 100 is negative

so we already know that the submarine is starting at -100 meters, which is going to be the y-intercept

ascend means to rise up signifying that the slope is going to be positive and we already know that the submarine is ascending 3 miles per minute

so the equation would look like this:

y = 3x - 100

7 0

3 years ago

Read 2 more answers

How do I determine z ∈ C:

saw5 [17]

Simplify the coefficient of z on the left side. We do this by rationalizing the denominators and multiplying them by their complex conjugates:

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3-2i}{1+i}\cdot\dfrac{1-i}{1-i} - \dfrac{5+3i}{1+2i}\cdot\dfrac{1-2i}{1-2i}$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{(3-2i)(1-i)}{1-i^2} - \dfrac{(5+3i)(1-2i)}{1-(2i)^2}$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 2i - 3i + 2i^2}{1-(-1)} - \dfrac{5 + 3i - 10i - 6i^2}{1-4(-1)}$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 5i + 2(-1)}2 - \dfrac{5 - 7i - 6(-1)}5$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2 - \dfrac{11 - 7i}5$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2\cdot\dfrac55 - \dfrac{11 - 7i}5\cdot\dfrac22$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{5 - 25i - 22 + 14i}{10}$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = -\dfrac{17 + 11i}{10}$

So, the equation is simplified to

$-\dfrac{17+11i}{10} z = \dfrac12 - \dfrac{2i}5$

Let's combine the fractions on the right side:

$\dfrac12 - \dfrac{2i}5 = \dfrac12\cdot\dfrac55 - \dfrac{2i}5\cdot\dfrac22$

$\dfrac12 - \dfrac{2i}5 = \dfrac{5-4i}{10}$

Then

$-\dfrac{17+11i}{10} z = \dfrac{5-4i}{10}$

reduces to

$-(17+11i) z = 5-4i$

Multiply both sides by -1/(17 + 11i) :

$\dfrac{-(17+11i)}{-(17+11i)} z = \dfrac{5-4i}{-(17+11i)}$

$z = -\dfrac{5-4i}{17+11i}$

Finally, simplify the right side:

$-\dfrac{5-4i}{17+11i} = -\dfrac{5-4i}{17+11i} \cdot \dfrac{17-11i}{17-11i}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{(5-4i)(17-11i)}{17^2-(11i)^2}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44i^2}{289-121(-1)}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44(-1)}{410}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 123i}{410}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 41\cdot3i}{410}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{1 - 3i}{10}$

So, the solution to the equation is

$z = -\dfrac{1-3i}{10} = \boxed{-\dfrac1{10} + \dfrac3{10}i}$

4 0

3 years ago