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Andrej [43]
3 years ago
12

The fifth term of an exponential sequence is 4375 and the second is 35 find the third term the fifth term the sum of the first f

ive terms
​
Mathematics
1 answer:
zimovet [89]3 years ago
8 0

Answer:

Wait

Step-by-step explanation:

i solve this

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The least common factor of x and x squared is x
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An electronic devise beeps every 4 seconds. Another devise beeps every 6 seconds if they both start beeping at the same time how
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3

Explanation:

The smallest whole number that 4 and 6 share when multiplied is 12
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3 years ago
a right triangle is removed from a rectangle to create the shaded region shown below. find the area of the shaded region. be sur
ser-zykov [4K]

Answer:

36

Step-by-step explanation:

Objective: Find missing dimensions of the right triangle using the then subtract that area of the triangle from the rectangle's area.

Using the definition of a rectangle, the left vertical side measure is 7 and right vertical side is 6. So the missing legs of the triangle is 4 and 3.

Apply triangle formula, base x height divided by 2.

\frac{4 \times 3}{2}  = 6

Area of rectangle is length x width so the area is

7 \times 6 = 42

Subtract 6 from 42.

42 - 6 = 36

3 0
2 years ago
ASAP PLSSS help me with this math question
rjkz [21]

Answer:

Answer is D

Step-by-step explanation:

just took the test and got it right

Please mark brainlest

8 0
3 years ago
A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0
2 years ago
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