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ASHA 777 [7]
4 years ago
10

Two jugs are filled with water. If you remove 1 liter of water from the first jug, then the two jugs contain the same amount of

water. If you remove 2 liters from the second, then the second jug would contain half as much as the first. How many liters of water are in the largest jug?
Mathematics
1 answer:
lyudmila [28]4 years ago
4 0
Let x be the first jug, y the second jug.

From first statement, subtracting 1 from x, makes them equal:
x - 1 = y

From second statement, subtracting 2 from y, makes it half of x:
x/2 = y-2

Solve system with substitution:
x/2 = (x-1) -2
x/2 = x - 3
x- x/2 = 3
x/2 = 3
x = 6

y = x-1 = 6-1 = 5

Therefore the largest jug contains 6 liters.
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What are the coordinates of the point on the directed line segment from (-4, - 7) to
lara [203]

Answer:

The coordinates of the point on the directed line segment from (-4, - 7) to

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\therefore P(x,y)=(\frac{-18}{5},\frac{-19}{5})

or

∴ PointP( x , y ) = ( -3.6, -3.8)

Step-by-step explanation:

Let he points be,

point A( x₁ , y₁) ≡ ( -4 ,-7)

point B( x₂ , y₂) ≡ (-3 , 1)

and Point P( x , y ) be the point on the line Segment AB Divides AB internally in the ratio 2 : 3 i. e m : n

To Find:

Point P( x , y ) = ?

Solution:

IF a Point P divides Segment AB internally in the ratio m : n, then the Coordinates of Point P is given by Section Formula as

x=\frac{(mx_{2} +nx_{1}) }{(m+n)}\\ \\and\\\\y=\frac{(my_{2} +ny_{1}) }{(m+n)}\\\\

Substituting the Given values we get

x=\frac{(2(-3) +3(-4)) }{(2+3)}\\ \\and\\\\y=\frac{(2(1) +3(-7)) }{(2+3)}\\\\x=\frac{-18}{5}\\ \\and\\\\y=\frac{-19}{5}\\\\\therefore P(x,y)=(\frac{-18}{5},\frac{-19}{5})

∴ PointP( x , y ) = ( -3.6, -3.8)

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