Answer:
You must survey 784 air passengers.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Assume that nothing is known about the percentage of passengers who prefer aisle seats.
This means that 
, which is when the largest sample size will be needed.
Within 3.5 percentage points of the true population percentage.
We have to find n for which M = 0.035. So
You must survey 784 air passengers.
Answer:
Step-by-step explanation:
h=11.4 in
r=5.1 in
v=3.14*r^2*(h/3)
V=3.14*5.1^2*(11.4/3)=3.14*26.01*3.8=310.35
When you lay them out then you know what you are dividing
Using the uniform distribution, it is found that there is a 0.3 = 30% probability that Samantha has to wait less than 4.5 minutes to catch the bus.
<h3>What is the uniform probability distribution?</h3>
It is a distribution with two bounds, a and b, in which each outcome is equally as likely.
The probability of finding a value of at lower than x is:
In this problem, the time is uniformly distributed between 0 and 15 minutes, hence the bounds are a = 0 and b = 15.
The probability that Samantha has to wait less than 4.5 minutes to catch the bus is given by:
More can be learned about the uniform distribution at brainly.com/question/13889040
Answer:
ncdjndndd
Step-by-step explanation:
jdsjkdsjdsjkjkds
