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luda_lava [24]
3 years ago
6

Identify the y-coordinate for the solution to the system of equations. Solve the system using substitution.

Mathematics
1 answer:
eimsori [14]3 years ago
6 0

Answer:

x = 23/5 OR 4.6

y = 157/15 OR 10.46

Step-by-step explanation:

x = 4x + 6x - 33 = 13

> 10x - 33 = 13

> 10x = 13 + 33

> 10x = 46

y = 4 (25/5) + 3y = -13

> 92/5 + 37 = -13

> 3y = -13 - 92/5

> 3y = - 157/5

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On the first day of school, Mr. Vilani gave his third- grade students 5 new words to spell. On each day of school after that, he
FinnZ [79.3K]
So, the best way to solve this problem is by creating a equation for which we can substitute any number of days. For this problem that equation would be W=5+3(t-1)
W=number of words
T=time or number of days
-1= This is here because we are already accounting for the first day of school so we need to have 1 less day than the number of days they have been in school.
So in 20 days the students had received
5+3(19) or 62words.
Answer: 62 words
6 0
3 years ago
Your city is represented in a coordinate plane where each unit represents 1 kilometer. The library is at (1, −2), the post offic
Rasek [7]

Answer:

The answer to your question is 10.7 units

Step-by-step explanation:

To solve this problem, just calculate the distance from the House to the Library, then the distance from the Library to the Post office and finally to the Post office to the house.

I hope this helps! Also, pls mark me as the brainliest!

AlSO IF YOU WANT THE STEP BY STEP EQUATION IT IS--->

dHL = \sqrt{(-2 + 3)^{2} + (-2 - 2)^{2}}

dHL = \sqrt{(1)^{2}+ (-4)^{2}}

dHL = \sqrt{17} = 4.1

dLP = \sqrt{(-2 -2)^{2} + (-2-2)^{2}}

dLP = \sqrt{(-4)^{2} + (-4)^{2}}

dLP = \sqrt{32} = 5.7

dPH = \sqrt{(2 + 3)^{2}+ (2 - 2)^{2}}

dPH = \sqrt{(5)^{2}+ (0)^{2}}

dPH = \sqrt{25}

dPH = 5

Minimum distance = 4.1 + 5.7 + 5

Minimum distance = 10.7

-----> PICTURE

6 0
3 years ago
Write all functions that are symmetric about the​ y-axis. Choose from the following six circular functions. yequals=sine xsinx​,
horsena [70]

Answer:

Hence the function only :

Secx and Cosx functions are symmetric about y-axis

And remaining functions are not symmetric about y-axis.

Step-by-step explanation:

Given:

Six circular function as :

y= sinx ,y=cosx , y=tanx,  y= cotx ,y=secx  y=cosecx

To Find:

Which functions are symmetric about the y-axis

Solution:

<em>The function is said to be symmetric about the y-axis is given by</em>

<em>f(x)=f(-x)</em>

Now

1)For y=sinx  i.e. f(x)=sinx

So put x=-x

f(-x)=sin(-x)

=-sinx

Hence f(x)≠f(-x)

This function is not symmetric about y-axis

2)For y=cosx ,i.e. f(x)=cosx

put  x=-x

f(-x)=cos(-x)...............(as value for x and -x cos value remain the same )

=cosx

hence f(x)=f(-x)

This function is symmetric to the y-axis

3)For y=tanx     i.e   f(x)=tanx

put  x=-x

f(-x)=tan(-x)

=-tanx

Hence f(x)≠f(-x)

This function is not symmetric about y-axis

4)For y=cotx  i.e.  f(x)=cotx

Using above observation,

f(x)≠f(-x)

This is not symmetric about y-axis

5)For y=secx  i.e f(x)=secx

f(x)=f(-x)

This function is symmetric about y-axis.

6) for y=cosecx

f(x)≠f(-x)

This function is not symmetric about y-axis

4 0
3 years ago
Angles 1 and 2 are complementary. If ∠1 measures 56°, what is the measure of ∠2?
Monica [59]
18 degrees
Step by step I got it right
4 0
3 years ago
I REALLY NEED HELP WILL GIVE EVERYTHING GOOD IF YOU HELP ON 2 MORE
DerKrebs [107]

Answer:

edit: i was wrong ignore me

4 0
3 years ago
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