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2 years ago

9

ANSWER BOTH QUESTIONS

1 answer:

mash [69]2 years ago

5 0

Answer:

a and c

Step-by-step explanation:

You might be interested in

You work 40 hours/week for 52 weeks and are given the option to be paid hourly or to go on salary. In which situation will you e

Kay [80]

Answer:

The best possible answer is A) $17.00 and hour with a $1,000 bonus.

Step-by-step explanation:

You can start by narrowing down the answers to the ones with the bonuses. The others are obviously less as it is the same pay without added bonus. Next we can determine the amount in answer A by multiplying the amount per hour by the number of hours in a week and by the number of weeks in a year.

$17.00 * 40 * 52 = $35,360

And then you add the $1,000 bonus.

Answer A Amount = $36,360

Now to find answer D amount, we multiply the total by the 10% bonus to find the bonus amount.

$32,000 * 10% = $3,200

Now we add that to the previous salary to get the overall D answer amount.

$32,000 + $3,200 = $35,200

As you can see, the amount in answer A is the larger amount.

8 0

2 years ago

Is the inequality true or false?<br><br> 8 + 5(2 x 4) ≥ 9 x 5

-BARSIC- [3]

9514 1404 393

Answer:

true

Step-by-step explanation:

Using the order of operations to evaluate the expressions, we have ...

8 + 5(8) ≥ 9(5)

8 +40 ≥ 45

48 ≥ 45 . . . . . true

5 0

2 years ago

Read 2 more answers

Which option below is not a potential risk of purchasing a used car?

vlada-n [284]

Answer:

used cars can have a lower initial cost

Step-by-step explanation:

it is not a risk/hinder to purchasing a used car

8 0

2 years ago

Can somebody help me out

Alex_Xolod [135]

First one is C (18 sq units)

Second one is A (12sq2 units)

7 0

2 years ago

The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0

3 years ago