0.4 because if it’s five or more, add one more. If it’s four or less, let it rest.
Answer:
1 st questions answer is third option
while the answer of other question is 3
Step-by-step explanation:
2nd qestions explanation
put value of x=2 in equation as x-2=0 from equation
(2)^3-6(2)^2+a2+10=2
8-24+a2+10=0
2a=-18+24
2a=6
a=3
1. 8r + 4 = 10 + 2r
-4 -4
8r = 6 + 2r
-2r -2r
6r = 6
R= 1
2. -2(x + 3) = 4x - 3
-2x - 6 = 4x - 3
+3 +3
-2x -3 = 4x
+2x +2x
-3 = 6x
————-
6 6
-1/2 = x
3. 5 + 3(q - 4) = 2(q + 1)
5 + 3q - 12 = 2q + 2
-7 + 3q = 2q + 2
+7 +7
3q = 2q + 9
-2q -2q
Q = 9
4. 7x - 4 = -2x + 1 + 9x - 5
7x - 4 = 7x - 4
-7x -7x
-4 = -4
+4 +4
0 = 0
Infinite answers
5. 8x + 6 - 9x = 2 - x -15
-x +6 = - 13 - x
+ x +x
6 = -13
No solution
1.)
=(x-8i)(x+8i)
x^2+8ix-8ix-64i^2
x^2-64i^2
x^2-64(-1)
x^2+64
2.)
=(4x-7i)(4x+7i)
16x^2+28ix-28ix-49i^2
16x^2-49i^2
16x^2-49(-1)
16x^2+49
3.)
=(x+9i)(x+9i)
x^2+9ix+9ix+81i^2
x^2+18ix+81(-1)
x^2+18ix-81
4.)
=(x-2i)(x-2i)
x^2-2ix-2ix+4i^2
x^2-4ix+4(-1)
x^2-4ix-4
5.)
=[x+(3+5i)]^2
(x+5i+3)^2
(x+5i+3)(x+5i+3)
x^2+5ix+3x+5ix+25i^2+15i+3x+15i+9
x^2+6x+10ix+30i+25i^2+9
x^2+6x+10ix+30i+25(-1)+9
x^2+6x+10ix+30i-25+9
x^2+6x+10ix+30i-16
Hope this helps :)
