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Over [174]
3 years ago
7

Which number does 9 have a value that is 1/10 times as small as it’s value in 891

Mathematics
2 answers:
Arisa [49]3 years ago
4 0

Answer:

9

Step-by-step explanation:

H T U

8. 9. 1

9 tens

1/10×10= 1

1 is a unit

I believe d answer is 9

pls like and follow

aliya0001 [1]3 years ago
4 0
The answer is 9 because yea
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Let r and s be the roots of x^2 - 6x + 2 = 0. Find (r - s)^2.
Sphinxa [80]

Answer: (r-s)^{2} = 28

Step-by-step explanation:

  • x^{2} -6x+9=-2+9
  • (x-3)^{2}=7
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  • (x-3) = -\sqrt{7}
  • x = 3 -\sqrt{7} <-- root.
  • (x-3) = \sqrt{7}
  • x = 3+\sqrt{7} <-- root.
  • [(3-\sqrt{7})-(3+\sqrt{7})]^{2}
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4 0
3 years ago
What is the basic ratio for 30:42
lianna [129]
30:42 is represented as 30/42
The lowest form for that is 5/7. Hope that helped. Good luck
6 0
3 years ago
If you had an individual who was gifted and talented in math, and well above the rest of your class, how might you use different
irakobra [83]

Answer:

See explanation below.

Step-by-step explanation:

Having students in the classroom who are at different levels of knowledge, interest, and ability can be managed by differentiated instruction. This method is a way of thinking that provides a framework where the instructor can set students with learning tasks that are at levels appropriate with the abilities and interests of each student. Each student can have a different type of class and different type of instruction with the differentiated instruction way of thinking.

A gifted and talented student might be assigned a higher math course, perhaps based on a math assessment for advanced placement. Then students that need to stay on the typical high school path of Algebra I, Geometry, Algebra II, and Trigonometry can do that.

Gifted students might take an alternate path with honors classes or trajectories involving Pre-Calculus or advanced placement Calculus, for example. In some instances, universities have allowed High School students to obtain college credit for some courses taken during High School.

Hope this helps! Have an Awesome Day!! :-)

6 0
3 years ago
WILL GIVE BRAINLIEST!!
alexandr402 [8]

its the 3rd answer!

hope this helps

7 0
3 years ago
Read 2 more answers
Suppose that a local trout population exhibits exponential growth by doubling every 4 years. Considering that the initial popula
antoniya [11.8K]
Okay, so this is just a basic multiplication problem. first, we need to divide to figure out how much the trout population grows after 1 year. If it doubles in 4 years, then it will rise by a quarter each single year. So to put that in terms of fractions, then for every year, the equation would be 250x1/4. So then we do the equation, coming up with 62.5. This means that the population rises roughly 63 fish a year. So after 1 year, you will have roughly 313 fish. (312.5 to be exact). Then to get that by ten years, we can just multiply the number that we got for one year by ten. 62.5x10=625. So then we add the 250 original trout, and 250+625=875. So after 10 years, there will be 875 trout.
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3 years ago
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