ASAP PLZ I'LL MARK BRAINLIEST<br><br>What is 8/9 ÷ 2/3?

At the fair, the ratio of males to females was 4:5. If there are 180 people at the fair, how mamy males are there?

Setler79 [48]

Answer:

80 males

Step-by-step explanation:

180 / 9 = 20

20 x 4 = 80

3 0

3 years ago

Read 2 more answers

kemdrick is an ecologist he spends 8 hours on friday how many hours he spending on saturday to average 11 hours per day

Sidana [21]

Answer:

$\boxed{13}$

Step-by-step explanation:

Let x = hours worked on Saturday

Then x + 8 = total hours on Friday and Saturday

$\text{Average} = \dfrac{ \text{total hours}} {\text{number of days}}\\\\11 = \dfrac{x + 8}{2}$

22 = x + 8

x = 13

Kendrick is working $\boxed{13}$ hours on Saturday.

5 0

3 years ago

I thought i knew this but i don't. Can someone help?

Goshia [24]

Im pretty sure the answer is B

3 0

3 years ago

Tensile-strength tests were carried out on two different grades of wire rod (Fluidized Bed Patenting of Wire Rods, Wire J., June

Shtirlitz [24]

Answer:

$t=\frac{(123.6-107.6)-(10)}{\sqrt{\frac{2^2}{129}+\frac{1.3^2}{129}}}=28.569$

$p_v =P(t_{256}>28.569) \approx 0$

So with the p value obtained and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true average strength for the 1078 grade exceeds that for the 1064 grade by more than 10 kg/mm2.

Step-by-step explanation:

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2 +10$

Alternative hypothesis: $\mu_1 >\mu_2 +10$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 \leq 10$

Alternative hypothesis: $\mu_1 -\mu_2>10$

Our notation on this case :

$n_1 =129$ represent the sample size for group AISI 1078

$n_2 =129$ represent the sample size for group AISI 1064

$\bar X_1 =123.6$ represent the sample mean for the group AISI 1078

$\bar X_2 =107.6$ represent the sample mean for the group AISI 1064

$s_1=2.0$ represent the sample standard deviation for group 1 AISI 1078

$s_2=1.3$ represent the sample standard deviation for group AISI 1064

And now we can calculate the statistic:

$t=\frac{(123.6-107.6)-(10)}{\sqrt{\frac{2^2}{129}+\frac{1.3^2}{129}}}=28.569$

Now we can calculate the degrees of freedom given by:

$df=129+129-2=256$

And now we can calculate the p value using the altenative hypothesis:

$p_v =P(t_{256}>28.569) \approx 0$

So with the p value obtained and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true average strength for the 1078 grade exceeds that for the 1064 grade by more than 10 kg/mm2.

7 0

3 years ago

Inga can earn $375 per week in a plant store, or she can earn 3% of total sales. How much would Inga have to sell to earn more i

qwelly [4]

Answer:

Inga will have to sell $12,533 to earn more in commission than in salary.

Step-by-step explanation:

As the commission is the percentage of sales amount so, need to calculate the minimum sales value required.

Igna's salary = $375

Commission rate = 3%

Sale to earn more than salary = $376 / 3% = $12,533.33

Igna has to make a minimum sale of $12,533 per week in order to earn more commission than her salary.

8 0

3 years ago

ASAP PLZ I'LL MARK BRAINLIESTWhat is 8/9 ÷ 2/3?​

ASAP PLZ I'LL MARK BRAINLIESTWhat is 8/9 ÷ 2/3?