For the rectangle you may do 2x(l+L)
for the cube ypu may apply the formula the second ne it should be more easier
<span>The ramp's horizontal distance is the distance in the x-axis. So the ramp's vertical distance I.e y-axis is 14 inches. And its length which is actually the hypotenuse ofthe right angled triangle 16 feet. But let's convert feet to inches first.
1 feet makes 12 inches
Hence 16 feet makes 192 inches.
From pythagoras
a^2 =b^2 + c^2 where a the hypotenuse is 192 and b is 14. C is the ramp's horizontal distance.
So we have (192)^2 = (14)^2 + c^2
C^2 = 192^2 - 14^2 = 36668
C = 191.48
From SOHCAHTOA. We have to use Sin
So sin theta = (14/192)
Theta = sin^(-1) (14/192) = 4.1815.
Yes, it meets the FAC standard since the ramp's angle is less than 4.78</span>
Percent means parts out of 100 so
10%=10/100
we know that 0.8358=8358/10000
8358/10000
make it over 100
move decimal
835.8/1000
83.58/100=83.58%
answer=53.58%
Answer:
200X = Y
Step-by-step explanation:
Since the insect in question can flap its wings 200 times per second, the equation that represents how many times it flaps its wings according to the time of flight is the following:
200X = Y
Thus, 200 is the number of times per second it flaps its wings, while X is the number of seconds in question. In turn, Y is the number of times it flaps its wings in the given time.
For example, if the insect were to fly for 5 seconds, the equation would work as follows:
200 x 5 = Y
1000 = Y
