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GenaCL600 [577]

3 years ago

7

6. The dimensions of a rectangular garden are 380ft x 250ft. If you want to walk around this garden to make 3 miles for a mornin

g walk, how many times should you walk? Note: I mile 5280f.

1 answer:

SSSSS [86.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

L=3(5280)/(2(380+250))

L=15840/1260

L=12.57

So to walk three miles one must walk around the garden 12.57 times.

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The next model of a sports car will cost 11.2% less than the current model. The current model costs $36,000. How much will the p

Tanzania [10]

Answer:

The decrease in the price will be $4032

The price of the next model is $31968

Step-by-step explanation:

The current model costs $36,000.

The next model of a sports car will cost 11.2% less than the current model

So, decrease in price = $11.2\% \times 36000$

= $\frac{11.2}{100} \times 36000$

=4032

So, the price of next model decrease by $4032

So, the price of the next model= 36000-4032 =31968

Hence the price of the next model is $31968

8 0

3 years ago

In this triangle, what is the value of x

shutvik [7]

Answer:

75.7 cm

Step-by-step explanation:

$\sin \: 63 \degree = \frac{x}{85} \\ \\ 0.8910065242 = \frac{x}{85} \\ \\ x = 0.8910065242 \times 85 \\ \\ x = 75.7355546 \\ \\ x = 75.7 \: cm$

5 0

3 years ago

Read 2 more answers

Consider a population list x with μx=10 and SDx = 1. A second population list, y, with μy=10 and SDy=2, is added to the first li

Basile [38]

Answer:

The combined standard deviation is 1.58114.

Step-by-step explanation:

The formula to compute the combined standard deviations of two different data sets is:

$SD_{c} =\sqrt{\frac{n_{X}S^{2}_{X}+n_{2}S^{2}_{Y}+n_{X}(\mu_{X}-\mu_{c})^{2}+n_{Y}(\mu_{Y}-\mu_{c})^{2}}{n_{X}+n_{Y}}$

Here $\mu_{c}$ is the combined mean given by:

$\mu_{c}=\frac{n_{X}\mu_{X}+n_{Y}\mu_{Y}}{n_{X}+n_{Y}}$

It is provided that the sample size is same for both the data sets, i.e. $n_{X} = n_{Y}=n$

Compute the combined mean as follows:

$\mu_{c}=\frac{n_{X}\mu_{X}+n_{Y}\mu_{Y}}{n_{X}+n_{Y}}\\=\frac{(n\times10)+(n\times10)}{n+n}}\\=\frac{20n}{2n}\\ =10$

Compute the combined standard deviation as follows:

$SD_{c} =\sqrt{\frac{n_{X}S^{2}_{X}+n_{2}S^{2}_{Y}+n_{X}(\mu_{X}-\mu_{c})^{2}+n_{Y}(\mu_{Y}-\mu_{c})^{2}}{n_{X}+n_{Y}}}\\=\sqrt{\frac{(n\times1^{2})+(n\times2^{2})+(n(10-10))+(n(10-10))}{n+n}}\\=\sqrt{\frac{n+4n}{2n} } \\=\sqrt{\frac{5n}{2n} } \\=\sqrt{\frac{5}{2}} \\=1.58114$

Thus, the combined standard deviation is 1.58114.

3 0

3 years ago

Solve for n<br><br>m = -2n-3/kn

Gekata [30.6K]

Answer:

$n=\frac{-km}{2k+3}$

Step-by-step explanation:

$n=-km/2k+3$

Hope this helps!

7 0

3 years ago

PLZZZZZ NEED HELP!!!!!!

tia_tia [17]

Answer:

Total annual premium = $1770.10

Step-by-step explanation:

Given the information in the problem, looking at the different categories of each level of insurance and the corresponding premium will give you the amounts for each part. To find the total annual premium, you need to find the sum of all the parts and then multiply this by the rating factor for his gender and age group.

Since he is purchasing 100/300/100 liability insurance, you need to first look at the 'Liability Insurance' table and locate the 100/300 option under 'Bodily Injury'. This premium is $450. Also, he is purchasing an additional 100 for Property damage which is an added premium of $375.

Next, he is getting collision insurance with a $100 deductible. This is the second column in the second table and has a premium of $215. He also wants comprehensive insurance with a $250 deductible which has a premium of $102.

Since he is a 26-year-old male, his rating is 1.55, so we will need to multiply the sum of his premiums by this number:

(450 + 375 + 215 + 102)1.55 = $1770.10

3 0

3 years ago