Answer:
We need a sample size of 564.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.
We need a sample size of n
n is found when 
So
Rounding up
We need a sample size of 564.
Answer:
3 cm
Step-by-step explanation:
38% of income tax on an income of $80,000 would be $30,400
84,000/15 = 5600
2 x 5600 = 11,200
The first person will get $11,200
Answer:
(a) The probability of a "Yes" answer, given that the person was a female is 0.16
(b) The probability that the respondent was a male, given that the response was a "No" is 0.3
Step-by-step explanation:
This problem can be solved using the definition of conditional probability
P(B|A) = P(A∩B) / P(A)
(a) In this case, event A is that the person is female and event B is that the answer of the person is "Yes".
P("Yes" | Female) = P(Female ∩ "Yes") / P(Female)
P("Yes" | Female) = (8/100)/(50/100)
P("Yes" | Female) = 8/50
P("Yes" | Female) = 0.16
(b) In this case, event A that the answer of the person is "No" and event B is that the person is male.
P(Male | "No") = P("No" ∩ Male) / P("No")
P(Male | "No") = (18/100)/(60/100)
P(Male | "No") = 18/60
P(Male | "No") = 0.3
