Segments AB,DC, and EC intersect at point C. Angle DCE measures 148. Find the value
1 answer:
Answer:
x = 16°
Step-by-step explanation:
We can see that AB is a straight line. The sum of angles on a straight line adds up to 180°
∠ACD + ∠DCE + ∠ECD = 180° (sum of angles on a straight line)
∠ACD = x, ∠DCE = 148, ∠ECD = x
substituting the respected values for the angles gives:
x + 148 + x = 180
2x + 148 = 180
subtracting 148 from both sides:
2x + 148 - 148 = 180 - 148
2x = 32
Dividing both sides by 2, to get x:
2x/2 = 32/2
x = 16°
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Answer:
m∠B = .
Step-by-step explanation:
Since the three sides of the triangle are given, then we apply cosine rule.
=
+
- 2ac Cos B
But, a = 660 cm, b = 680 cm, and c = 100 cm.
So that;
=
+
-2(660 x 100) Cos B
462400 = 435600 + 10000 - 132000 Cos B
462400 = 445600 - 132000 Cos B
132000 Cos B = 445600 - 462400
= -16800
Cos B =
= -0.1273
B = -0.1273
=
Thus, measure of ∠B is .