The prove to show that the area of the shaded portion is 18x - 30 is as follows: 3x² + 13x - 30 - 3x² + 5x = 18x - 30
<h3>How to find the area of the shaded region?</h3>
The area of the shaded region can be represented as follows:
area of the shaded region = area of rectangle - area of triangle
Therefore,
area of the rectangle = (x + 6)(3x - 5)
area of the rectangle = 3x² - 5x + 18x - 30
area of the rectangle = 3x² + 13x - 30
area of triangle = 1 / 2 × 2x × 3x - 5
area of triangle = 3x² - 5x
Therefore,
area of the shaded portion = 3x² + 13x - 30 - 3x² + 5x
area of the shaded portion = 18x - 30
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Answer:
it would be 36-45 and 56-64
200,000 = 158,000(1.06)^x
Divide both sides by 158,000
1.2658 = 1.06^x
Take the log of both sides and use the power rule to bring down the exponent (x) to the front.
log 1.2658 = x log 1.06
Divide both sides by log 1.06
log (1.2658)/log(1.06) = x
x = 4 years
CHECK
y = 158,000(1.06)^4
y = 199,471.36
An outlier is a datapoint outside of the first or third quartile +/- 1.5 the inter quartile range
25 33 39 40 41 41 45 46 48 49 51 52 67 73 79
46 is at the center-> median
everything left of it:
25 33 39 40 41 41 45
40 at center=Q1
right of Q2:
48 49 51 52 67 73 79
52 at center=Q3
IQR=Q3-Q1=52-40=12
Q1-1.5*IQR=40-1.5*12=40-18=22
Q3+1.5*IQR=52+1.5*12=52+18=60
so everything <22 or >60 are outliers
so 67,73 and 79 are outliers
Answer:
There is not enough information to determine the mean, the median is 28.
There is not enough information to determine the mean absolute deviation, the interquartile range is 18
Step-by-step explanation:
The box plot given has a skewed distribution, this means that both the mean and median values are not the same. From a box plot, the median value Can be obtained as the point in between the box.
From the box plot given, the marked point in between the box is 28 cm
Hence, Median = 28 cm
The mean cannot be inferred from the skewed box plot.
There is also not enough information to determine the mean absolute deviation ;
The interquartile range:
(Q3 - Q1)
Q3 = upper quartile, the endpoint of the box = 40
Q1 = the starting point of the box = 22
IQR = Q3 - Q1
IQR = 40 - 22 = 18
